Question

idenitfy the margin of error( round to one decimal place) is it square miles? miles? miles ler hour?

construct a 90% confidence interval for the population mean?

interpret

of 14 10 complete HW Score: 41.84, 5.86 of 14 Score: 0 of 1 pt X 6.2.18-T Question in a random sample of twee people, the mean driving dance to work was 24.1. 90% confidence interval for the population mean Interpret the results and the sandard deviation was 75 miles. Assume the population is normally dibuted and use the distribution to find the margin of nor and construct Identify the main ofen

Answer 1

I Solution : n=12 x = 24.1, 5=7. 5 t -distribution Here, C=0.90 .251-0-1-0-90 = 0.10 itair,n-1 = to: 10/2, 12-1 =10796 Now, Margin of essor (m.E.) = toz = 1.795 / 7.5 / 2 ME = 3.9 90% confidence interval is C:I. = X I M.E. = 29.5 3.9 C'I. = (20.2, 28.0)| conclusion :- with 90% confidence, it can be said that the population mean driving distance to work Cin miles) es between the intervals endpoints liScanned with CamScanner