Question

Wenzhou prepares 200 mL of a solution of SnCl4in which the concentration ofchloride ions is 0.240M.a) What is the molarity of the SnCl4solution (i.e. what should the bottle be labeled)?b) What mass of SnCl4did Wenzhou use?

Answer 1

Given concentration of chloride ion is 0.240M

1 mole of SnCl4 contains four chloride ions

SnCl4 ---> Sn4+ + 4Cl-

So [SnCl4]=[Cl-]/4 = 0.240M / 4 = 0.060 M

(a) Therefore the molarity of SnCl4 is 0.060M

(b) Molar mass of SnCl4= atomic mass of An+(4*atomic mass of Cl)

= 118.7+4(35.5)

= 260.7 g/mol

Number of moles of SnCl4,n= molarity*volume of solution in L

= 0.060M*200 mL*10^-3 L/mL

= 0.12 moles

So mass of SnCl4,m= number of moles * Molar mass

= 0.12 moles*260.7 g/mol

= 3.128 g