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cholesterol comparison. list plasma cholesterol level( mmol/m3) in
two independent groups. plot these data on a common stem. then
compare group location and spreads
group 1 ( mildly hypercholesterolemic)
6.0 6.4 7.0 5.8 6.0 5.8 5.9 6.7 6.1 6.5 6.3 5.8
group 2 ( control)
6.4 5.4 5.6 5.0 4.0 4.5 6.0
3:4 page 58 cholesterol comparison. list plasma cholesterol level( mmol/m3) in two independent groups. plot these...
In a study on cholesterol levels a sample of 12 men and women was chosen. The plasma cholesterol levels (mmol/L) of the subjects were as follows: 6.0, 6.4, 7.0, 5.8, 6.0, 5.8, 5.9, 6.7, 6.1, 6.5, 6.3, and 5.8. We assume that these 12 subjects constitute a simple random sample of a population of similar subjects. Find a 95% confidence interval for the population standard deviation of the plasma cholesterol levels.
A comparison was made of the average length of stay (in days) for the years 2000, 2005, 2010, and 2015 between males and females (ages 45–64) for seven diagnoses. The data indicates: 2000 2005 2010 2015 Males: Malignant Neoplasm 9.2 9.4 8.2 7.0 Diabetes Mellitus 7.9 7.3 6.6 6.5 Diseases of the Heart 6.5 5.8 5.0 4.8 Cerebrovascular disease 10.2 10.0 6.2 6.8 Pneumonia 8.0 7.9 7.2 6.9 Injuries and poisoning 6.6 7.2 5.8 5.5 Fractures 7.5 7.2 6.7 6.3...
A comparison was made of the average length of stay (in days) for the years 2000, 2005, 2010, and 2015 between males and females (ages 45–64) for seven diagnoses. The data indicates: 2000 2005 2010 2015 Males: Malignant Neoplasm 9.2 9.4 8.2 7.0 Diabetes Mellitus 7.9 7.3 6.6 6.5 Diseases of the Heart 6.5 5.8 5.0 4.8 Cerebrovascular disease 10.2 10.0 6.2 6.8 Pneumonia 8.0 7.9 7.2 6.9 Injuries and poisoning 6.6 7.2 5.8 5.5 Fractures 7.5 7.2 6.7 6.3...
In a digital communication system, probability density function of the two level signal received in the receiver is: PR(v) = PS(v)*PN(v) = [0.4δ(v+1) + 0.6δ(v-4)]*η(v). And , η(v) is the noise that added to the message sign as the additive Gaussian noise with a value of zero and an effective value of 3. (* symbol means convolution process, in the solution of this problem you can use the below Q function table.) , η(v) = A) Plot the probability density...
the way this is worded confuses me. Will there be one problem where male weight is x and female bmi is y. or is it two problems where x&y is male weight and bmi for the 1st problem, and x&y is female weight and bmi for problem 2? 2. Using the data set of the Health Exam Results, conduct the following of weight (WT) and Index (BMI). Number the data set from 1 to 40, and select the following individuals:...
On Blackboard under "Course Content / Homeworks and Practice Tests" there is an Excel file titled "HW 6 Data" with monthly stock return data to be used for this question: What is Deckers Outdoor Corporation's [DECK] beta? Round to two decimal places. [Hint: Take S&P 500 as a proxy for the market, and use the beta formula from the book. You will need to use two Excel functions: STDEV.S and CORREL] Numeric Answer S&PS00 DECK NKE SBUX -1.5% Ос-19 7.4%...
2. Using the data set of the Health Exam Results, conduct the following analysis between the variables of weight (WT) and Body Mass Index (BMI). Number the data set from 1 to 40, and select the following individuals: . Set 1 (Malo): 1, 5, 10, 13, 15, 18, 19, 24, 29, 31, 32, 33 .Set 2 (Fomalo): 4, 9, 15, 16, 17, 22, 23, 29, 33, 37, 38, 40 Draw a scatter diagram of the sample of 12 data set...
Please help with solving Question 1 (A-C) Thank you! Unless otherwise specified in the problem, you may assume that all solutions are at 25°C. 1. 50.0 mL of a pH 6.00 carbonic acid buffer is titrated with 0.2857 M NaOH, requiring 17.47 mL to reach the second equivalence point. a. Calculate the molarity of carbonic acid and bicarbonate in the original buffer. Carbonic acid: Bicarbonate: b. Calculate the pH of the solution after a total of 100.0 mL of 0.2857...