Question

python code( using functions please)!

Rules of the game: - This game requires a dice. The goal of the game is to collect the correct number of coins to create a dollar. Players take coins based on a roll of the dice. The numbers on the dice correlate to the coin values as follows:  1—penny  2—nickel  3—dime  4—quarter  5— ( pick a random card from 1 to 4): o 1 = penny o 2 = nickel o 3 = dime o 4 = quarter  6—lose a turn - Players take turns rolling the dice and adding coins. - The winner becomes the first player to reach exactly one dollar. - If taking a coin would put the player over a dollar, the player loses the turn.

requirements: 1- Need to have 2 players 2- Every turn the dice will be rolled randomly (value will vary between 1 – 6). 3- Depending on the dice value, you will update the total number of coins each player has. 4- Will keep rolling the dice and adding the coins, until one of the players wins. (Reach exactly $1). 5- By adding the coins each turn, if the total number of coins exceeds $1, then skip that turn and do not increase the coins total. Automatically it will be the other player’s turn. 6- Need to display the total coins for each player after each round. 7- After announcing the winner, ask players if they want to play again. (Yes/No). 8- Need to validate all user inputs.

Answer 1

Program Screen Shot:

Sample Output:

Program Code to Copy:

# 1 dollar considered as 100 cents to avoid floating point errors
import random

# returns one random integer 1 to 6 inclusive
def roll_dice():
   return random.randrange(1,7)

# converts and returns coin value in cents
def get_value(coin):
   value = [1, 5, 10, 25] # [penny,nickel,dime,quarter] in cents
   if coin == 6: # player loses turn
       return 0
   if coin == 5: # player picks a random card 1 to 4
       coin = random.randrange(1,5) # random 1 to 4
   return value[coin-1] # -1 because lists start at index 0

# exchanges player 0 to 1 or 1 to 0 where 0 means player 1 and 1 means player 2
def change_player(player):
   if player == 0:
       return 1 # player 2
   return 0 # player 1

# the engine that controls the entire game
def play_game():
player = 0 # start with player 1 by default for the first round
coin_value = [0,0] # initially 0 for both players
play_again = True

while play_again:
print('Player 1 total = ',coin_value[0],'cents, player 2 total = ',coin_value[1],'cents')
print('Player', player+1, 'enter P to roll the dice: ',end=' ')
play = input('').upper() == 'P'
if play: # user has entered P
coin = roll_dice() # get coin
print('\ndice shows: ',coin)
value = get_value(coin) # get value of coin in cents
if value == 0: # dice showed 6
print('Player', player+1, 'loses the turn!')
elif (coin_value[player] + value) > 100: # excess
print('Value exceeds $1, Player', player+1, 'loses the turn!')   
elif (coin_value[player] + value) <= 100: # correct roll
coin_value[player] = coin_value[player] + value # increase the coins
  
# ending the game or going for another round
if coin_value[player] == 100: # exactly $1
print('Congratulations!, player',player+1, 'has won the game.')
coin_value = [0,0] # reset the scores
play_again = input('Play Again? (Yes/No): ').upper() == 'YES' # players decide

# next turn or round starts with a different player
player = change_player(player) # next turn

# invoke the engine function start the game
play_game()

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