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In the Iodination of Salicylamide, active iodine was created by the action of sodium hypochlorite on...

In the Iodination of Salicylamide, active iodine was created by the action of sodium hypochlorite on sodium iodide. When the reaction was complete, 10% sodium thiosulfate solution was added to the reaction mixture before acidification. What is the role of sodium thiosulfate in this procedure?

A. It tests the pH of the mixture.

B. It destroys excess sodium hypochlorite.

C. It removes water from the organic layer.

D. It protects salicylamide from the harsh acid.

I have seen that the answer is not B so what is it and why?

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