What is the pH of a solution of 1.00L of water with 0.0973 moles of NaOH...

Question

Question

What is the pH of a solution of 1.00L of water with 0.0973 moles of NaOH in it ?

Answer 1

Answer #1

Step1 : to calculate the molarity of NaOH

Molarity= 0.0973/1 (mol/L)

= 0.0973 M

Since NaOH is strong base dissociate completely

So [OH^-] = 0.0973 M

P^OH = - log(0.0973) = 1.01

P^H = 14 - 1.01 = 12.99

Answer 2

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