Question

1. Arrange the following in increasing order of vapor pressure, starting from lowest to highest.

C₆H₁₄ -C₂H₆ -C₁₀H₂₂ -CH₄ -C₁₅H₃₂

2. Name the all the intermolecular forces in each of the following substances:

a. BaCl₂

b. H₂O

c. CH₄

d. HI

e. NH₃

3. Arrange the following substances in increasing order of melting point, starting from the lowest to highest.

C₂H₅OH N₂ CH₃Cl C₃H₈

4. Which type of intermolecular force is the most important attraction in each of the following:

a. CH₃CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₂CH₃

b. CH₃Cl

c. CH₃OH

d. C₂H₅OCH₃

e. CH₃CH₂F

f. HCOOH

5. Which would have the greater vapor pressure:

a. CH₃COOH or CH₃CH₂Cl

b. CH₃CH₂OH or CH₃OCH₃

Answer 1

The order of increasing vapour pressure is as follows

C15H32<C10H22<C6H14<C2H6<CH4

This is because C15H32 have strogest intermolecular force that is vander waal force here due to largest size and CH4 have weakest vander waal force due to smallest size.

This is because

The stronger the intermolecular forces, the stronger the interactions that hold the substance together, the lower the vapor pressure of a liquid at the given temperature, and the harder it is to vaporize a substance.