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Given: Ksp(Ag2CrO4) = 1.2×10-12 Ksp(BaCrO4) = 2.1×10-10 For a solution which is initially 0.060 M in...

Given:
Ksp(Ag2CrO4) = 1.2×10-12
Ksp(BaCrO4) = 2.1×10-10

For a solution which is initially 0.060 M in Ba2+ and 0.060 M in Ag+, it is desired to precipitate one of these ions as its chromate (CrO42−) salt to the maximum possible degree without precipitating any of the other cation. From this solution, which ion can be selectively first-precipitated by controlled addition of CrO42− and, ideally, what is the maximum possible percentage of that ion which can be exclusively so precipitated?
(Assume that there is no change in the total volume of the solution.)

Ba2+ or Ag+

%???

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