Q3: Implement a Full Adder using: (5 pts each) F(A,B,C)=(A+B+C)(A’+C’)(B’+C’) A. A 3x8 active high decoder...

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Q3: Implement a Full Adder using: (5 pts each) F(A,B,C)=(A+B+C)(A’+C’)(B’+C’) A. A 3x8 active high decoder...

Q3: Implement a Full Adder using: (5 pts each)

F(A,B,C)=(A+B+C)(A’+C’)(B’+C’)

A. A 3x8 active high decoder

B. A 3x8 active low decoder

C. With two 2x4 Active high decoders.

engineering Electrical-Engineering

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Answer 1

Answer #1

We can implement 3x8 decoder using one inverter and two 2x4 decoders. Place inverter in the place of first decoder then A and A' will act as a enable inputs to two other decoders.

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Answer 2

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Q3: Implement a Full Adder using: (5 pts each) F(A,B,C)=(A+B+C)(A’+C’)(B’+C’) A. A 3x8 active high decoder...