The yield (larger-the-better) on an old chemical process for five days is 61, 63, 58, 57,...
The yield (larger-the-better) on an old chemical process for five days is 61, 63, 58, 57, and 60. The new process had yields of 54, 56, 52, 56, 53, 51, 54, 53, and 52. Does the new process have a better S/N ratio?
| a |
Y |
|
| b |
N |
Homework Answers
The yield (larger-the-better) on an old chemical process for five days is 61, 63, 58, 57, and 60.
S/N ratio = 
= 59.8/2.1354
= 28
The new process had yields of 54, 56, 52, 56, 53, 51, 54, 53, and 52.
S/N ratio =
= 53.4444/1.6405
= 32.58
Yes, the new process have a better S/N ratio.
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#### Code in R ###
mental.csv
Pre.test
Post.test
Treat
72
74
Control
58
57
Control
66
74
Control
51
56
Control
30
28
Control
48
40
Control
58
61
Control
51
50
Control
38
40
Control
56
56
Control
68
72
Control
36
38
Control
53
53
Control
65
72
Control
32
24
Control
64
62
Control
58
55
025-050R
58
57
025-050R
56
57
025-050R
73
59
025-050R
49
42
025-050R
53
49
025-050R
28
29
025-050R
31
43...
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#### Code in R ###
mental.csv
Pre.test
Post.test
Treat
72
74
Control
58
57
Control
66
74
Control
51
56
Control
30
28
Control
48
40
Control
58
61
Control
51
50
Control
38
40
Control
56
56
Control
68
72
Control
36
38
Control
53
53
Control
65
72
Control
32
24
Control
64
62
Control
58
55
025-050R
58
57
025-050R
56
57
025-050R
73
59
025-050R
49
42
025-050R
53
49
025-050R
28
29
025-050R
31
43...
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