Question

Python please

For this program, we will be making lists for the local Zoo. You have been provided with 4 lists of data already created for you. Using this data, we update the data at this Zoo. YOU MUST USE LIST FUNCTIONS FOR REMOVING TO RECEIVE YOUR FULL POINTS!

Input:

• A type of animal -- This information should be provided in response the question: "What animal are we removing?"
• A number corresponding to the selection of a menu number (see menu below) 1) Do not remove animal from social list 2) Only remove animal from social list 3) Remove from all lists animal appears in

Output:

• If user selected "1":
• Remove the animal from any non-social list the animal appears in.
• Display all lists in the order: Carnivore, Herbivore, Omnivore, Social
• If user selected "2":
• Remove the animal from the social list if the animal is in that list.
• Display all lists in the order: Carnivore, Herbivore, Omnivore, Social
• If user selected "3":
• Remove the animal from any list the animal appears in.
• Display all lists in the order: Carnivore, Herbivore, Omnivore, Social
• If user makes an invalid select, print the message That was not an option

HINT: Remember, lists are ordered, so DO NOT sort your output!

LAB

Answer 1

Python code:

Herbivore = ['Rabbit','Dog','Cat']
Carnivore = ['Lion','Dog','Cat','Cheetah']
Omnivore = ['Dog','Cat','Monkey']
Social = ['Monkey','Dog','Horse']
print("Initial lists:")
print(Herbivore)
print(Carnivore)
print(Omnivore)
print(Social)
print("---------------------------------------------------")
animal = input("What animal are we removing?")
print("MENU:")
print("1) Do not remove animal from social list ")
print("2) Only remove animal from social list")
print("3) Remove from all lists animal appears in all")
option = int(input("Enter an option : "))

if(option == 1):
if(animal in Herbivore):
Herbivore.remove(animal)
if(animal in Carnivore):
Carnivore.remove(animal)
if(animal in Omnivore):
Omnivore.remove(animal)
print("Removing animal from non Social lists")
print("Displaying lists:")
print(Herbivore)
print(Carnivore)
print(Omnivore)
print(Social)
elif(option == 2):
if(animal in Social):
Social.remove(animal)
print("Removing animal from Social lists")
print("Displaying lists:")
print(Herbivore)
print(Carnivore)
print(Omnivore)
print(Social)
elif(option == 3):
if(animal in Herbivore):
Herbivore.remove(animal)
if(animal in Carnivore):
Carnivore.remove(animal)
if(animal in Omnivore):
Omnivore.remove(animal)
if(animal in Social):
Social.remove(animal)
print("Removing animal from all lists")
print("Displaying lists:")
print(Herbivore)
print(Carnivore)
print(Omnivore)
print(Social)
else:
print("That was not an option")
  
Execution screenshots:

Note:Please like the answer.Thank you.Have a nice day.