1.this question contains two independent part.
a)Given two NFA’s M1 and M2, show how you will construct an NFA M such that L(M) = L(M1) ∩ L(M2).
b)for the following languages over the alphabet Σ = {a, b}, give a DFA that recognizes that language
L3 consists of strings in which every odd position contains b
1.this question contains two independent part. a)Given two NFA’s M1 and M2, show how you will...
Automata Question. Over the alphabet Σ = {0, 1}: 1) Give a DFA, M1, that accepts a Language L1 = {all strings that contain 00} 2) Give a DFA, M2, that accepts a Language L2 = {all strings that end with 01} 3) Give acceptor for L1 intersection L2 4) Give acceptor for L1 - L2
Part B - Automata Construction Draw a DFA which accepts the following language over the alphabet of {0,1}: the set of all strings such that the number of 0s is divisible by 2 and the number of 1s is divisible by 5. Your DFA must handle all intput strings in {0,1}*. Here is a methodical way to do this: Figure out all the final states and label each with the shortest string it accepts, work backwards from these states to...
Let L1 = {ω|ω begins with a 1 and ends with a 0}, L2 = {ω|ω has length at least 3 and its third symbol is a 0}, and L3 = {ω| every odd position of ω is a 1} where L1, L2, and L3 are all languages over the alphabet {0, 1}. Draw finite automata (may be NFA) for L1, L2, and L3 and for each of the following (note: L means complement of L): Let L w begins...
UueSLIORS! 1. Find the error in logic in the following statement: We know that a b' is a context-free, not regular language. The class of context-free languages are not closed under complement, so its complement is not context free. But we know that its complement is context-free. 2. We have proved that the regular languages are closed under string reversal. Prove here that the context-free languages are closed under string reversal. 3. Part 1: Find an NFA with 3 states...
1. Design an NFA (Not DFA) of the following languages. a) Lw E a, b) lw contain substring abbaab) b) L- [w E 10,1,2) lsum of digits in w are divisible by three) c) L-(w E {0,1,2)' |The number is divisible by three} d) The language of all strings in which every a (if there are any) is followed immediately by bb. e) The language of all strings containing both aba and bab as substrings. f L w E 0,1every...
Question 1: Every language is regular T/F Question 2: There exists a DFA that has only one final state T/F Question 3: Let M be a DFA, and define flip(M) as the DFA which is identical to M except you flip that final state. Then for every M, the language L(M)^c (complement) = L( flip (M)). T/F Question 4: Let G be a right linear grammar, and reverse(G)=reverse of G, i.e. if G has a rule A -> w B...
1) 2) Give formal descriptions (5-tuples) for the DFAs shown in figure below: 3) Give the state diagrams of DFAs recognizing the following languages over ? = {0, 1}: a) LÆ b) L? c) {e, 1001} d) {e, 101, 1001} e) {w : w has prefix 10} f) {w : w does not contain the substring 011} 4) Give the state diagrams of DFAs recognizing the following languages over ? = {0, 1}: a) {w: |w| ? 5} b) {w...
I need to construct a deterministic finite automata, DFA M, such that language of M, L(M), is the set of all strings over the alphabet {a,b} in which every substring of length four has at least one b. Note: every substring with length less than four is in this language. For example, aba is in L(M) because there are no substrings of at least 4 so every substring of at least 4 contains at least one b. abaaab is in...
Any answer that involves a design for a Finite Automaton (DFA or NFA) should contain information about the following five components of the FA (corresponding to the 5-tuple description): i) The set of states Q; ii) the alphabet Σ; iii) the start state; iv) the set of final states F; v) the set of transitions δ, which can be either shown in the form of a state diagram (preferred) or a transition table. You can either present the answer in...
. Terminals: • Any character from the alphabet is a terminal . Epsilon (E) is expressed as: le, leps or lepsilon The empty set is expressed as: lemp or lemptyset • Operations (R is a regular expression) o Union is expressed as RIR o Star as R* o Concatenation as RR o Plus as R+ Problem For the following regular expression: (Elab Over the alphabet: {a,b} Give 2 words that the regular expression recognizes and 3 words that the regular...