Use the given data to find the minimum sample size required to estimate a population proportion or percentage.
Margin of error:
0.080.08;
confidence level
9090%;
ModifyingAbove p with caretp
and
ModifyingAbove q with caretq
unknown
solution:-
given that margin of error E = 0.08
the value of 90% confidence from z table is 1.645
here we have not p and q values so
take p = 0.5 the q = 1- p = 1 - 0.5 = 0.5
formula for sample size
=> n = (z/E)^2 * P * Q
=> n = (1.645/0.08)^2 * 0.5 * 0.5
=>n = 106
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