The rate constant of a reaction is 4.75 × 10−5 L/mol·s at 195 °C and 9.85 × 10−3 L/mol·s at 258 °C. What is the activation energy of the reaction? Enter your answer in scientific notation.
Answer
175.1kJ/mol
Explanation
From Arrhenius equation we get the following relation
log(k1/k2) = Ea/2.303R(1/T2 - 1/T1)
where,
k1 = rate constant 1, 4.75×10-5M-1s-1
k2 = rate constant 2 , 9.85 ×10-3M-1s-1
T1 = temperature 1, 195℃ = 468.15K
T2 = temperature 2 , 258℃ = 531.15K
R = gas constant , 8.314J/K mol
Ea = activation energy
substituting the values
log(4.75×10-5M-1s-1/9.85×10-3M-1s-1) = (Ea/2.303×8.314J/Kmol)(1/531.15K - 1/468.15K)
- 2.3168= (Ea/19.147J/molK) (-0.0002534K-1)
Ea/19.147J/mol = 9142.9
Ea = 175.1kJ/mol
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