Given : 2 K + Cl 2 2 KCl H = - 873.0 kJ
For the reaction of 2 mol K , q = - 873.0 kJ.
We can use ratio ( - 873.0 kJ / 2 mol K ) as conversion factor to find out the heat released when 5 mol K reacts,
H = 5 mol K ( - 873.0 kJ / 2 mol K ) = - 2182.5 kJ
ANSWER : When 5 mol K reacts with chlorine , 2182.5 kJ energy is released.
consider the following reaction: 2K+Cl2-> 2KCl H=-873.0 kj how much heat is released if 5 moles...
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