Using the data below, determine the settling time for the second order system:
Time (s) | Amplitude |
0 | 0 |
3.16E-30 | 7.47E-57 |
0.000201 | 3.02E-05 |
0.001206 | 1.08E-03 |
0.006229 | 2.72E-02 |
0.031023 | 0.51248 |
0.061826 | 1.425188 |
0.099249 | 2.359214 |
0.140376 | 2.920516 |
0.183532 | 3.1091 |
0.227754 | 3.104428 |
0.278362 | 3.045984 |
0.342708 | 3.002737 |
0.425039 | 2.99524 |
0.506407 | 2.998975 |
0.615447 | 3.000331 |
0.767501 | 3.000468 |
0.920226 | 2.999749 |
1.056668 | 2.999555 |
1.193109 | 3.000021 |
1.388517 | 3.001741 |
1.510863 | 3.000185 |
1.63321 | 2.999723 |
1.786723 | 2.999804 |
1.960731 | 3.000734 |
2.085173 | 3.000352 |
2.209616 | 2.999888 |
2.40442 | 2.998924 |
2.577002 | 3.000302 |
2.683482 | 3.000888 |
2.789963 | 3 |
2.960359 | 2.999382 |
3.135232 | 2.999128 |
3.281634 | 3.001378 |
3.415906 | 3.000791 |
3.535948 | 2.999741 |
3.699181 | 2.999306 |
3.853134 | 3.000228 |
3.981996 | 3.000497 |
4.110857 | 2.999997 |
4.296683 | 2.998962 |
4.428887 | 2.999783 |
4.561092 | 3.000297 |
4.72347 | 3.000408 |
4.88724 | 2.999339 |
5.010703 | 2.999576 |
5.134166 | 3.000088 |
5.33167 | 3.001282 |
5.503343 | 3.000199 |
5.611168 | 2.999008 |
5.718993 | 2.999955 |
5.875068 | 3.000391 |
6.051371 | 3.000747 |
6.207337 | 2.998803 |
6.323786 | 2.999509 |
6.440234 | 3.000128 |
6.624253 | 3.000821 |
6.795031 | 2.999731 |
6.907399 | 2.999302 |
7.019767 | 3.000008 |
7.197998 | 3.000716 |
7.340338 | 3.000231 |
7.482678 | 2.999582 |
7.64539 | 2.999345 |
7.795936 | 3.00055 |
7.923749 | 3.000449 |
8.051561 | 2.999917 |
8.25067 | 2.998398 |
8.417714 | 2.999504 |
8.5514 | 3.001983 |
8.660474 | 3.000198 |
8.788976 | 2.99972 |
8.948557 | 2.999693 |
9.11716 | 3.000711 |
9.240338 | 3.000398 |
9.363516 | 2.999903 |
9.559555 | 2.998835 |
9.732019 | 3.000026 |
9.83944 | 3.000942 |
9.946862 | 3.000024 |
10 | 2.999919 |
first copy the data in a .txt file and name it data.txt.
load the data file into MATLAB work space and plot the data as given below.
load data.txt;
figure;plot(data(:,1),data(:,2));grid
on;xlabel('time');ylabel('Amplitude');
The figure is plotted below.
It is obseved that the response is plotted from 0 to 10 is but the settling time is somewhere close to 1 second. Therefore zoom into the plot during the transient period as below plot.
Based on 2% settling time criteria, from above figure it is observed that settling time is 0.3175 second.
Using the data below, determine the settling time for the second order system: Time (s) Amplitude...
Using the data below, determine the settling time for the second order system: Time (s) Amplitude 0 0 3.16E-30 7.47E-57 0.0002009509145 3.02E-05 0.001205705487 1.08E-03 0.00622947835 2.72E-02 0.0310234533 0.5124798924 0.06182619079 1.42518817 0.09924865943 2.359213825 0.1403755911 2.920516231 0.1835315875 3.109100448 0.2277539458 3.104428489 0.2783618436 3.045984383 0.3427082024 3.002737367 0.4250393709 2.995240372 0.5064069484 2.998974783 0.6154469095 3.000330972 0.7675008987 3.000468019 0.9202263312 2.999748795 1.0566679 2.999554627 1.193109468 3.000021214 1.388516791 3.001741122 1.51086337 3.000185181 1.633209948 2.999722844 1.786722545 2.999803766 1.960731087 3.000734198 2.085173347 3.000352327 2.209615607 2.99988824 2.404419919 2.998923741 2.577001965 3.000301735 2.683482331 3.000888184 2.789962698 2.999999922 2.960358508 2.999381635...
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