Question

A random sample of 250 persons yields a sample mean of 110 and a sample standard...

A random sample of 250 persons yields a sample mean of 110 and a sample standard deviation of 10. Construct three different confidence intervals to estimate the population mean, using 95%, 99%, and 99.9% levels of confidence. What happens to the interval width as the confidence level increases? Why?

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A random sample of 250 persons yields a sample mean of 110 and a sample standard...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A random sample of 43 observations is used to estimate the population variance. The sample mean...

    A random sample of 43 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 68.5 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 95% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval to b. Construct...

  • A random sample of 24 observations is used to estimate the population mean. The sample mean...

    A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 128.4 and 26.80, respectively. Assume that the population is normally distributed. [You may find it useful to reference the t table.) a. Construct the 95% confidence interval for the population mean. (Round intermediate calculations to at least 4 decimal places. Round "t" value to 3 decimal places and final answers to 2 decimal places.) Confidence interval...

  • A simple random sample with n=56 provided a sample mean of 21.0 and a sample standard...

    A simple random sample with n=56 provided a sample mean of 21.0 and a sample standard deviation of 4.7 . a. Develop a 90% confidence interval for the population mean (to 1 decimal). b. Develop a 95% confidence interval for the population mean (to 1 decimal). c.Develop a 99% confidence interval for the population mean (to 1 decimal). d. What happens to the margin of error and the confidence interval as the confidence level is increased?

  • A simple random sample with n = 50 provided a sample mean of 23.5 and a sample standard deviation of 4.2.

    A simple random sample with n = 50 provided a sample mean of 23.5 and a sample standard deviation of 4.2. a. Develop a 90% confidence interval for the population mean (to 1 decimal). b. Develop a 95% confidence interval for the population mean (to 1 decimal). c. Develop a 99% confidence interval for the population mean (to 1 decimal). d. What happens to the margin of error and the confidence interval as the confidence level is increased? 

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$127.00. Assume the population standard deviation is ​$19.20. Construct a​ 90% confidence interval for the population mean. The​ 90% confidence interval...

  • A. A random sample of 32 different juice drinks has a mean of 98 calories per...

    A. A random sample of 32 different juice drinks has a mean of 98 calories per serving and a standard deviation of 31.5 calories. Construct a 99% confidence interval of the population mean number of calories per serving, and interpret the 99% confidence interval in 1 sentence: B. A random sample of 50 standard hotel rooms in Philadelphia, PA, has a mean nightly cost of $189.99 and a standard deviation of $35.25. Construct a 95% confidence interval of the mean...

  • How many computers? In a simple random sample of 185 households, the sample mean number of...

    How many computers? In a simple random sample of 185 households, the sample mean number of personal computer ls was 1.64. assume the population of the standard deviation is 0.47 a) construct a 99.9% confidence interval for the mean number of personal computers. round the answer to at least two decimal places. a 99.9% confidence interval for the mean number of personal computers is ---< mean <----- 2) In a sample of 75 clamps, the mean step to complete this...

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of ​$135.00 . Assume the population standard deviation is ​$15.90 . A.) the 90% confidence interval is B.) the 95% confidence interval...

  • 26. Birth Weights A simple random sample of birth weights in the United States has a mean of 3433...

    *without using interval functions on calculator* 26. Birth Weights A simple random sample of birth weights in the United States has a mean of 3433 g. The standard deviation of all birth weights is 495 g a. Using a sample size of 75, construct a 95% confidence interval estimate of the mean birth weight in the United States. b. Using a sample size of75,000, construct a 95% confidence interval estimate of the mean birth weight in the United States. c....

  • #17 You are given the sample mean and the population standard deviation. Use this information to...

    #17 You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Which interval is​ wider? If​ convenient, use technology to construct the confidence intervals. A random sample of 34 gas grills has a mean price of ​$648.20 Assume the population standard deviation is ​$56.70 The​ 90% confidence interval is ​(______​,______).

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT