Determine the concentration (ppm) of the Pb added to the coin digestion.
Pb %: 0.7
coin weight: 0.2001g
Determine the concentration (ppm) of the Pb added to the coin digestion. Pb %: 0.7 coin...
The action level for lead (Pb) in water is 0.015 ppm. What is the concentration in molarity (M, mol/L)? Respond with the correct number of significant figures in scientific notation.
If a one-liter sample of a chemical waste had a concentration of 5000 ppm (parts per million), how much water would have to be added to dilute the sample to an acceptable concentration of 5 ppm? Show work below.
To a solution of Pb (NO3)2, whose concentration is 1 x 10-6 M, an alkaline iodine salt is added until the concentration of jodide ions reaches 2 x 10 M. Determine if a precipitate of Said sample. Kps data (Pbl2) = 1.4 x 10-4
Suppose that you started with 5 ml of 100 ppm Cu 2+ solution and added it to 0.1g of soil. After mixing, you filter it and find that the concentration of the filtered solution is 5 ppm Cu 2+ . From the above scenario, calculate the mass of Cu 2+ bound to the soil. 2. Calculate the Kdist.
A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard. The signal readings for these were 0.115 units and 0.321 units respectively. Sufficient internal standard was added to an unknown sample solution to make it contain 15.00 ppm internal standard. This solution gave readings for the analyte and internal standard of 0.266 and 0.275 units respectively. Determine the concentration of the analyte in the unknown sample.
A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO), (aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 14.12 g PbCI,(s) is obtained from 200.0 mL of the original solution Calculate the molarity of the Pb(NO), (aq) solution. concentration:
A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard. The signal readings for these were 0.115 units and 0.321 units respectively. Sufficient internal standard was added to an unknown sample solution to make it contain 15.00 ppm internal standard. This solution gave readings for the analyte and internal standard of 0.266 and 0.275 units respectively. Determine the concentration of the analyte in the unknown sample. Select one: O A. 1.71 ppm OB. None...
A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)2(aq) Pb ( NO 3 ) 2 ( aq ) , until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 10.47 g PbCl2(s) 10.47 g PbCl 2 ( s ) is obtained from 200.0 mL 200.0 mL of the original solution. Calculate the molarity of the Pb(NO3)2(aq) Pb ( NO 3 ) 2 ( aq ) solution. concentration: M
A standard solution with a concentration of 12.5 ppm gave a fluorescence emission intensity of 5.227 x 104 counts at 457 nm. An unknown sample was diltued by placing 5 mL of the sample into a 250 mL volumetric flask and diluted to the mark. The resulting solution gave an emission intensity of 3.921 x 104 counts at 457 nm. Determine the concentration of analyte in the unknown sample in ppm.
2. The absorbance of a series of standard solutions of a substance X vs concentration [X], in ppm) is measured. The data is as following: Concentration (ppm) 10.0 20.0 30.0 40.0 50.0 Absorbance 0.105 0.198 0.330 0.402 0.533 An unknown solid sample (0.1050 g) containing substance X was dissolved in 5.0 mL acidic solution and then transferred to a 100.0 mL volumetric flask and filled with deionized water to the mark. The absorbance of this solution is 0.378. What is...