Consider a computer system with a 32-bit logical address and 8-KB page size. The system supports up to 1GB of physical memory. How many entries are there in a page table?
Given computer system has 32-bit logical address
Logical Address Space size = 2^32 bytes
Physical Memory size = 1GB = 2^30 bytes
Page size = 8 KB = 2^3 * 2^10 bytes = 2^13 bytes
a)
Number of entries in single-level page table = Number of pages
in the Logical Memory
= 2^32 bytes / 2^13 bytes = 2^19 entries
b)
Number of entries in inverted page table = number of pages/frames in the Physical memory
= 2^30 / 2^13 = 2^17 entries
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