Chapter 8, Consider a computer system with a 32-bit logical addressand 4-KB page size. The system supports up to 512 MB of physicalmemory. How many entries arethere in each of the following?
a.A conventional single-level page table.
b.An inverted page table.
32 -bit ==>2^32 Bytes --logical memory space
given page size is 4KB = 2^12Bytes
given physical memory size =512MB
=2^29bytes
so number of pages =2^32/2^12
=2^20 pages
number of frames =2^29/2^12
=2^17
a.number of entries in A conventional single-level page table are=2^20 (number of pages)
b.number of entries in a inverted page table =2^17 (number of frames)
-With 32 bit virtual addresses and 4KB pages, 512MB physicalmemory,
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