Given a 32 bit processor, with 2 MB of physical RAM split into 512 frames. What is the size of the single level page table, in entries, if the maximum addressable virtual memory space is 16MB
Given a 32 bit processor, with 2 MB of physical RAM split into 512 frames. What...
Given a 32 bit processor, with 2 MB of physical RAM split into 512 frames. What is the size of the single level page table, in entries, if the maximum addressable virtual memory space is 16MB
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How many bits the virtual address contain? How many bits the physical address contain? bs Suppose now that some pages from the process have been brought into main memory as shown in the following figure: Virtual memory Physical memory Page table Frame #...
3. Virtual Memory (20 points) An ISA supports an 8 bit, byte-addressable virtual address space. The corresponding physical memory has only 256 bytes. Each page contains 32 bytes. A simple, one-level translation scheme is used and the page table resides in physical memory. The initial contents of the frames of physical memory are shown below. VALUE address size 8 bit byte addressable each byte of addressing type memory has its own address 32 B page size physical memory size 256...
The RISC-V 32-bit architecture supports virtual memory with 32-bit virtual addresses mapping to 32-bit physical addresses. The page size is 4Kbytes, and page table entries (PTEs) are 4 bytes each. Translation is performed using a 2-level page table structure. Bits 31:22 of a virtual address index the first-level page table. If the selected first-level PTE is valid, it points to a second-level page table. Bits 21:12 of the virtual address then index that second-level page table. If the selected second-level...
Consider a virtual memory system with the following properties: 36 bit virtual byte address, 8 KB pages size, and 32 bit physical byte address. Please explain how you determined your answer. a. What is the size of main memory for this system if all addressable frames are used? b. What is the total size of the page table for each process on this processor, assuming that the valid, protection, dirty, and use bits take a total of 4 bits and...
A computer system has a 36-bit virtual address space with a page size of 8K, and 4 bytes per page table entry. How many pages are in the virtual address space? What is the maximum size of addressable physical memory in this system? If the average process size is 8GB, would you use a one-level, two-level, or three-level page table? Why? Compute the average size of a page table in part c above
A certain byte-addressable computer system has 32-bit words, a virtual address space of 4GB, and a physical address space of 1GB. The page size for this system is 4 KB. Assume each entry in the page table is rounded up to 4 bytes. a) Compute the size of the page table in bytes. b) Assume this virtual memory system is implemented with a 4-way set associative TLB (Translation Lookaside Buffer) with a total of 256 address translations. Compute the size...
4. Assume that we have a machine with the following memory specifications: Virtual addresses are 32 bits wide Physical addresses are 26 bits wide . Page size is 16 Kbytes 4/A) How many pages are in the virtual memory space? 4/B) How many page frames are in the physical memory space? 4/C) If each page table entry consists of a physical frame number, 1 present/absent bit Answers Pages .Page Frames and 1 dirty/clean bit (which shows if the page has...
Given: 2 MB of physical R/W memory, composed of multiple 256KB chips, a CPU with a 21 bit address bus and an 8 bit data bus. Answer the following questions. h. (1 pt) Suppose I replaced the 256K RAM chip at the highest address, with a 256K EPROM chip, what would the address be of the lowest byte in the EPROM?
Given: 2 MB of physical R/W memory, composed of multiple 256KB chips, a CPU with a 21 bit address...
Problem #1 (25 points) Address Space, Memory Consider a hypothetical 18-bit processor called HYP18 with all registers, including PC and SP, being 18 bits long. The smallest addressable unit in memory is an 8-bit byte. A. (4 points) What is the size of HYP18's address space in bytes and KB? How many address lines does HYP18 require? Address space: Bytes Address space: KB (KiloBytes). Address bus lines: B. (6 points) Assume that first quarter of the address space is dedicated...