The number of disintegrations per second of C14 nuclei in a 1 milligram sample from a...
The number of disintegrations per second of C14 nuclei in a 1 milligram sample from a dead tree is 85.3% of that of the disintegrations of 1 milligram sample from a living tree. What year did the tree die?
Homework Answers
Decay constant of C-14 = 3.84 * 10-12 s-1
We have the relation: A = A0 * e-kt
Where A is the current activity (0.853A0), A0 is the initial activity, k is the decaty constant and t is the time
Using the given values, 0.853 * A0 = A0 * e-3.84 * 10-12 * t
Solving: 0.159 = 3.84 * 10-12 * t
t = 4.141 * 1010 s = 1312.98 years, therefore the tree dies 1313 years ago menaing in the year 717 AD
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