In C,
`Hey,
Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries
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#include <stdio.h>
#include<math.h>
#include<stdlib.h>
#include<string.h>
int main(int argc,char* argv[])
{
int i,l=argc-1;
for(i=1;i<=l;i++)
{
char
first[(int)(floor(strlen(argv[i])/2)+1)],last[(int)(ceil(strlen(argv[i])/2)+1)];
int n=strlen(argv[i]);
int j;
for(j=0;j<n/2;j++)
{
first[j]=argv[i][j];
}
first[n/2]='';
for(j=n/2;j<n;j++)
{
last[j-n/2]=argv[i][j];
}
last[n-n/2]='';
if(n!=1)
{
if(strcmp(first,last)>0)
{
printf("%s %s ",last,first);
}
else
printf("%s %s ",first,last);
}
else
printf("%s ",argv[i]);
}
return 0;
}
Kindly revert for any queries
Thanks.
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