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according to one survey the mean serum cholesterol level for US adults was 202.6 with a...

according to one survey the mean serum cholesterol level for US adults was 202.6 with a standard deviation of 48.2. a simple random sample of 102 adults is chosen. find the 52 percentile for the sample mean. round to one decimal place.

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Answer #1

z value at 52% = 0.05

mean = 202.6 , s = 48.2 . n = 102

z = (x - mean)/(s/sqrt(n))

0.05 = (x - 202.6)/(48.2/sqrt(102))
x = 202.6 + 0.2386

x = 202.8

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