A painting of mass 3.20 kg hangs on a wall. Two thin pieces of wire, each...
A painting of mass 3.20 kg hangs on a wall. Two thin pieces of wire, each 0.250 m long, connect the painting's center to two hooks in the wall. The hooks are at the same height and are 0.330 m apart. When the painting hangs straight on the wall, how much tension is in each piece of wire? In N
The answer is not 28.97N
Homework Answers
From figure,
By force balance in vertical direction,
T*sin
+ T*sin =
W
here, T = tension in each piece of wire
W = weight of painting = m*g
W = 3.20*9.81 = 31.39 N
from figure, cos =
(0.330/2)/0.250 = 0.66
then, sin = sqrt(1 -
(cos)^2) = sqrt(1 -
0.66^2) = 0.75
So, T*0.75 + 0.75*T = 31.39
T = 31.39/(0.75+0.75)
T = 20.93 N
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