A random sample of 12 winter days in Denver gave a sample mean pollution index of 43. Previous studies show that the population standard deviation is 21. For Englewood, a random sample of 14 winter days gave a pollution index of 36. Previous studies show that the population standard deviation is 15. Assume the pollution index is normally distributed in both Englewood and Denver. What formula would you use to calculate the test statistic?
A random sample of 12 winter days in Denver gave a sample mean pollution index of...
A random sample of n 1-14 winter days in Denver gave a sample mean pollution index x1 43. Previous studies show that σ1 . 23. For Englewood (a suburb of Denver , a random sample of n2 . 16 winter days gave a sample mean pollution index of x2 = 36 Previous studies show that σ2 13. Assume the pollution index is normally distributed in both Englewood and Denver (a) Do these data indicate that the mean population pollution index...
A random sample of n, - 11 winter days in Denver gave a sample mean pollution Index x - 43. Previous studies show that 0,- 14. For Englewood (a suburb of Denver), a random sample of n, - 17 winter days gave a sample mean pollution Index of xy - 51. Previous studies show that 0, - 16. Assume the pollution Index is normally distributed in both Englewood and Denver, Do these data indicate that the mean population pollution index...
A random sample of 20 acres gave a mean yield of wheat equal to 41.5 bushels per acre with a standard deviation of bushels. Assuming that the yield of wheat per acre is normally distributed, construct a 90% confidence interval for the population mean Round your answers to two decimal places. to i bushels per acre
A sample of 21 tree heights gave a sample mean of 26.1 m. Suppose the population standard deviation is 6.2 m. Construct a 80% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 80% confident that the true population mean tree height lies somewhere between metres and metres.
A sample of 14 tree heights gave a sample mean of 21.5 m. Suppose the population standard deviation is 5.8 m. Construct a 99% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 99% confident that the true population mean tree height lies somewhere between metres and 3 metres.
6. (5 pts.) A random sample of 30 days gives a variance for the pollution indices of 29.3. The pollution indices are normally distributed. Find a 98% confidence interval for the variances of pollution indices.
6. (5 pts.) A random sample of 30 days gives a variance for the pollution indices of 29.3. The pollution indices are normally distributed. Find a 98% confidence interval for the variances of pollution indices.
A test on a random sample of 50 water balloons yielded a sample average weight of 1.2 pounds. Prior studies have shown that the population standard deviation is 0.2 pounds. Assume that water balloon weight is normally distributed. Construct a 95% confidence interval of the population mean?
A random sample of 51 newborn babies was taken at the Hospital. The sample mean was 6.87 pounds and the standard deviation was 1.76 pounds. In previous studies, the mean newborn weight was found to be 7.5 pounds. a. Does the sample from the Hospitalindicate that the mean newborn weight is less than what was found in previous studies? Use a hypothesis test with the 7-step method and the critical value method to verify if there is enough significant evidence...
To test H0: σ= 2.3 versus H1 : σ> 2.3, a random sample of size n = 18 is obtained from a population that is known to be normally distributed. Complete parts (a) through (d). (a) If the sample standard deviation is determined to be s- 2.1, compute the test statistic. z(Round to three decimal places as needed,) TO test H0: ơ-1.4 versus H1 : ơt 1.4, a random sample of size n-21 is obtained from a population that is...