Question

A sample of 14 tree heights gave a sample mean of 21.5 m. Suppose the population standard deviation is 5.8 m. Construct a 99%

0 0
Add a comment Improve this question Transcribed image text
Answer #1

% 3D 21.5 । 5.8 ०.०० CI= x + 12 (ल (ie २).5 + 2. 005x (_58 ) ।५ CIC 112.5 २. 5) 7 L.C.S. Searned withreatsCATTTET

Add a comment
Know the answer?
Add Answer to:
A sample of 14 tree heights gave a sample mean of 21.5 m. Suppose the population...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A sample of 18 tree heights gave a sample mean of 20.3 m. Suppose the population...

    A sample of 18 tree heights gave a sample mean of 20.3 m. Suppose the population standard deviation is 7.0 m Construct a 99% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 99% confident that the true population mean tree height lies somewhere between metres and D3 metres.

  • A sample of 21 tree heights gave a sample mean of 26.1 m. Suppose the population...

    A sample of 21 tree heights gave a sample mean of 26.1 m. Suppose the population standard deviation is 6.2 m. Construct a 80% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 80% confident that the true population mean tree height lies somewhere between      metres and      metres.

  • A sample of 11 tree legits gave a sample mean of 243 m Support Construct a...

    A sample of 11 tree legits gave a sample mean of 243 m Support Construct a 30% confidence interval for the population mean web Wec. normally distributed Round to one digitate the decimal point Answer: We are 80% confident that the true population mean treballen som metres and B nent Quid & Save

  • At a large grocery store, based on a sample of size 25, the cashier error has...

    At a large grocery store, based on a sample of size 25, the cashier error has a sample mean of 29.1 dollars per day and a standard deviation of 5.8 dollars. Find a 96% confidence interval for the population cashier error. You may assume that the cashier errors are normally distributed Answer: We are 96% confident that the true population mean of cashier error lies somewhere between and Round to the nearest whole dollar, do not include dollar symbol in...

  • A simple random sample of size 14 has mean 3.67 and standard deviation 1.75. The population...

    A simple random sample of size 14 has mean 3.67 and standard deviation 1.75. The population is approximately normally distributed. Construct a 99% confidence interval for the population mean. 1. The parapmeter is the population (choose one) mean, standard deviation, variable, proportion 2. The correct method to find the confidence interval is the (choose one) z, t, chi square method

  • At a large grocery store, based on a sample of size 15 , the cashier error...

    At a large grocery store, based on a sample of size 15 , the cashier error has a sample mean of   27.6 dollars per day and a standard deviation of   5.0 dollars. Find a 87% confidence interval for the population cashier error. You may assume that the cashier errors are normally distributed. Answer: We are 87% confident that the true population mean of cashier error lies somewhere between        and       

  • The heights of newborn babies are normally distributed with an unknown population mean and a population...

    The heights of newborn babies are normally distributed with an unknown population mean and a population standard deviation of 10 centimeters. A random sample of babies from the population produces a sample mean height of x¯=50 centimeters. Use Excel to find the value of z that should be used to calculate a confidence interval with a 90% confidence level. Round your answer to three decimal places.

  • A random sample of 107 lightning flashes in a certain region resulted in a sample average...

    A random sample of 107 lightning flashes in a certain region resulted in a sample average radar echo duration of 0.77 sec and a sample standard deviation of 0.50 sec. Calculate a 99% (two-sided) confidence interval for the true average echo duration u. (Round your answers to two decimal places.) sec Interpret the resulting interval. We are 99% confident that the true population mean lies above this interval. We are 99% confident that this interval contains the true population mean....

  • A random sample of 109 lightning flashes in a certain region resulted in a sample average...

    A random sample of 109 lightning flashes in a certain region resulted in a sample average radar echo duration of 0.82 sec and a sample standard deviation of 0.41 sec. Calculate a 99% (two-sided) confidence interval for the true average echo duration u. (Give answers accurate to 3 decimal places.) (717 923 X) Interpret the resulting interval. o We are 99% confident that this interval does not contain the true population mean. . We are 99% confident that this interval...

  • Reming The You are reading an old report about tree heights in a certain area. The...

    Reming The You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 25.8 m and 28.0 m. The sample size is given as 37 trees, and the document states that the population standard deviation is assumed to be 5.5 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT