A sample of 11 tree legits gave a sample mean of 243 m Support Construct a...

Question

Question

Answer 1

Answer #1

Given х = 24.3 5.7 1 11 Level of significance Crtical value ze = a. = 0.2 1.28155 = 1.28 (Using excel =NORM.S.INV(a/2)) 80 %

Answer 2

Similar Homework Help Questions

A sample of 21 tree heights gave a sample mean of 26.1 m. Suppose the population...

A sample of 21 tree heights gave a sample mean of 26.1 m. Suppose the population standard deviation is 6.2 m. Construct a 80% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 80% confident that the true population mean tree height lies somewhere between metres and metres.
A sample of 18 tree heights gave a sample mean of 20.3 m. Suppose the population...

A sample of 18 tree heights gave a sample mean of 20.3 m. Suppose the population standard deviation is 7.0 m Construct a 99% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 99% confident that the true population mean tree height lies somewhere between metres and D3 metres.
A sample of 14 tree heights gave a sample mean of 21.5 m. Suppose the population...

A sample of 14 tree heights gave a sample mean of 21.5 m. Suppose the population standard deviation is 5.8 m. Construct a 99% confidence interval for the population mean tree height. We can assume that the tree heights are normally distributed. Round to one digit after the decimal point. Answer: We are 99% confident that the true population mean tree height lies somewhere between metres and 3 metres.

A through D please Objective 4: Construct and Interpret a Confidence Interval for a Population Mean...

A through D please Objective 4: Construct and Interpret a Confidence Interval for a Population Mean 9.2 Estimating a Population Mean 9.2.17 O of 1 Point Question Help A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 114, and the sample standard deviation, s, is found to be 10. (a) Construct an 80% confidence interval about if the sample size, n, is 23. (b) Construct...
A random sample of 20 acres gave a mean yield of wheat equal to 41.5 bushels...

A random sample of 20 acres gave a mean yield of wheat equal to 41.5 bushels per acre with a standard deviation of bushels. Assuming that the yield of wheat per acre is normally distributed, construct a 90% confidence interval for the population mean Round your answers to two decimal places. to i bushels per acre
In a random sample of 11 people, the mean driving distance to work was 25.2 miles...

In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)

The point estimate of the population mean is $62,339. Sample size 350. Standard deviation 19331.91502 Construct...

The point estimate of the population mean is $62,339. Sample size 350. Standard deviation 19331.91502 Construct a 99% confidence interval for the population mean. Assume that your data is normally distributed and Ïƒ is unknown.
For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c)...

For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. Assume that x is normally distributed x= 27, n=9, 0 = 6 a. Find a 95% confidence interval for the population mean The 95% confidence interval is from to (Round to two decimal places as needed.) b. Identify and interpret the margin of error. The margin of error is (Round to two decimal places as needed.) Interpret the margin of error. Choose the...
A large hospital wholesaler, as part of an assessment of workplace safety, gave a random sample...

A large hospital wholesaler, as part of an assessment of workplace safety, gave a random sample of 64 of its warehouse employees a test (measured on a O to 100 point scale) on safety procedures. For that sample of employees, the mean test score was 75 points, with a standard deviation of 15 points. Determine and interpret a 90% confidence interval for the mean test score of all the company's warehouse employees. (Please keep at least four decimal places). Question...

A sample of 18 joint specimens of a particular type gave a sample mean proportional limit...

A sample of 18 joint specimens of a particular type gave a sample mean proportional limit stress of 8.45 MPa and a sample standard deviation of 0.77 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) MPa Interpret this bound. O with 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints...