1) For the first statement as in question, it is an example of exothermic reaction because it involves release of heat even if you are standing far away from the reaction. Therefore reaction for first statement is exothermic reaction.
2) Since to dissolve salt, we apply some energy for stirring. This apply of energy will dissolve the salt completely. Therefore it is endothernic reaction since you supply energy to it.
In multiple question we solve only one or two questions at a time. If you find any mistake please mention in the comment box. Thanks.
A piece of metal is dropped into a test tube of light-blue liquid. The piece of...
Show Calculation of % ethanol in each tube below. A. Preparation of Standards (4.5pt) # %(v/v) Tube Ethanol Observations after heating Oil. turned light orange. LOL turned light orange 2.04. turned burnt orange 3.0% turned dark Yellow green 4.01. turned light green 5.01. turned dark blue igreen 6.07 turned light blue 7.01 turned light blue 8.07. turned light blue Show calculation of %(v/v) ethanol in each tube below (2.25pt): PROCEDURE: NOTES: Follow all standard safety precautions. Discard all waste into...
Measurement and Accuracy Procedure Obtain 5 large test tubes (all the same size), a test tube rack, 3 beakers of colored water A-C, and 3 graduated cylinders. With a Sharpie, label the tubes 1-5 Measure 25 mL of solution from beaker A (red) using a clean graduated cylinder. Pour into tube 1. Measure 28 mL of solution from beaker B (yellow) using a clean graduated cylinder. Pour into tube 3. Measure 22 mL of solution from beaker C (blue) using...
how do you do this ? Some Calculations You started out with a known amount of harium chloride and sodium sulfate. How much solid product should you collect? Show your calculations. How much did you collect? What is your percent yield? Which reactant should be the limiting reagent? Which reactant should be the excess reagent? Proving the identity of the Limiting and Excess Reagents There are two scenarios for the identity of the contents of the beaker containing the filtrate....
PART B The operations in this part will take place in the hood. To avoid traffic problems, plan ahead and work efficiently to occupy the hood for a minimal time. After making a set of test tube additions, step back to mix the tubes and allow others to have access to the materials. Clean and rinse the four-inch (small) and six-inch (medium) test tubes from your drawer. Use three of the four-inch tubes to observe the colors of the halogen...
Calorimetry Materials: Styrofoam cup & lid Digital thermometer Metal sample Graduated cylinder Beaker Test tube with stopper Heating setup for beaker Behind a calorimetry experiment is the known occurrence of heat flow from a warm object to a cooler object. Heat scales with the amount of matter and also depends on the resistance of an object to change temperature. Temperature is just the average of the amount of energy contained inside a given area. Heat is represented by the letter...
Part C. Benedict's Test. Test Tube Samp Prediction Observations Results (+ or -) 2-hydroxybutanal Benzaldehyde Propanone Cyclohexanone Unknown Part D. Iodoform Test. Test Sample Tube 1 2-hydroxybutanal Prediction Observations Results (+ or -) Benzaldehyde Propanone Cyclohexanone Unknown Experiment 12 Identification of Aldehydes and Ketones O the b e t theader of each holding your breath as a st beward your nose. Record the derson the specified memes from O Ta Test g shes between ones that contain a methyl group...
Explain your answer in terms of LeChatelier's principle. c) The above solution is divided equaly into three test tubes A, B. and Test tube "A is placed in an ice bath kept at 0 "C, test tube "B is kept at room temperature (25 °C) and test tube "C is placed in a boiling hot water bath maintained at 100 "C. The folowing are the colors of the solutions observed in each case. Solution "A" remained pink, solution "B" became...
Part IV. Decomposition Into a test tube, place about 2 mL of 3% hydrogen peroxide along with a pea size amount of Mnog Manganese dioxide, the common name, is used as a catalyst. Remember, that a catalyst is used to lower the activation energy of a reaction, thereby speeding up the reaction. It does not get con- sumed in the reaction and therefore is not part of your balanced chemical equation. It is written above the reaction arrow in a...
1 Reaction C: Copper(II) Hydroxide to Copper(IT) Oxide Observations: The solntich goes from a light blue to a dark blue. when heated the solution turns to a green/black color. Balanced Molecular Equation: Balanced Net lonie Equation: Reaction D: Copper(IT) Oxide to Copper(II) Sulfate Observations: "The back sond is dissolved in the acid. This creates a light blue / Clear solurich Balanced Molecular Equation: Balanced Net Ionic Equation: Reaction E: Copper(II) Sulfate to Copper Metal (and Dissolution of excess Mg) Observations:...
are theses correct? please correct me if they are not. Results Fe Test Tube 2: FeSCN (aa) SCN () Fe Chemical equation: Explanation: The equilibrium shifted toward the increased the due to the addition of Fe(NO,)) because it of the Test Tube 3: FESCN 0) SCN () (as Chemical equation: Fe(ag) Explanation: Test Tube 4: Chemical equation: Fe(agk FeSCN( (aq)h Explanation: Test Tube 5: Chemical equation: Fe"( SCN () FESCN 3+ + (sq) Explanation: Test Tube 6 Chemical equation: Fe(a...