Question

A 15.8 gram sample of krypton gas has a volume of 913 milliliters at a pressure of 2.03 atm. The temperature of the Kr gas sample is ____ C.

Answer 1

Mass of Krypton = 15.8 gm

Molar mass of Krypton = 83.798 g/mol

Moles of Krypton = 15.8 g / 83.798 g/mol = 0.188548 Moles

The following equation can be used to calculate the temperature.

PV= nRT

P = Pressure in atm                       V= Volume in Liter

n = no of moles               R = 0.0821 L atm K-1 Mol-1

T = Temperature in Kelvin

P = 2.03 atm V = 913 ml = 0.913 Liter n = 0.188548 Moles   

T = PV/nR

T = 2.03 atm x 0.913 Liter / 0.08206 L atm K-1 Mol-1 x 0.188548 Moles

T = 119.78 K = -153.22 ⁰C

The temperature of the Kr gas sample is -153.22 Degree Celcius