Question

A sample of 80.0 mL of krypton gas, Kr, is at 756 torr and 18.5C. What is the new volume if the pressure is decreased to 185
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Answer #1

Given:

Pi = 756 torr

Pf = 185 torr

Vi = 80.0 mL

Ti = 18.5 oC

= (18.5+273) K

= 291.5 K

Tf = 11.0 oC

= (11.0+273) K

= 284 K

use:

(Pi*Vi)/(Ti) = (Pf*Vf)/(Tf)

(756 torr*80 mL)/(291.5 K) = (185 torr*Vf)/(284.0 K)

Vf = 318.5076 mL

Answer: 319 mL

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