Question

To test the claim that sons are taller than their fathers on average, a researcher randomly...

To test the claim that sons are taller than their fathers on average, a researcher randomly selected 13 fathers who have adult male children. She records the height of both the father and son in inches.

  1. What is (are) the parameter(s) of interest? Choose one of the following symbols m (the population mean);mD(the mean difference from paired (dependent) data);m1 - m2 (the difference of two independent means) and describe the parameter in context of this question in one sentence.
  2. Depending on your answer to part (a), construct one or two relative frequency histograms. Remember to properly title and label the graph(s). Copy and paste these graphs into your document.
  3. Depending on your answer to part (a), construct one or two boxplots and copy and paste these graphs into your document.
  4. Does the boxplot (or do the boxplots) show any outliers? Answer this question in one sentence and identify any outliers if they are present.
  5. Considering your answers to parts (c) and (e), is inference appropriate in this case? Why or why not? Defend your answer using the graphs in two to three sentences data set is below

    Data Set: Son's Height   Father's Heigh
    64.4   79
    69.2   67.1
    76.4   70.9
    69.2   66.8
    78.2   72.8
    76.9   70.4
    71.8   70.3
    79   70.1
    75.8   79.5
    72.3   65.5
    69.2   65.4
    66.9   69.1
    64.5   74.5
0 0
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Answer #1

The histograms are:

The histogram for Son's Height and Father's height are skewed.

The boxplots are:

The heights have a greater number of variations for Son's data.

The test to be performed is the independent t-test.

The hypothesis being tested is:

H0: µ1 = µ2

H1: µ1 > µ2

The output is:

Son's Height   Father's Height
71.831 70.877 mean
5.071 4.576 std. dev.
13 13 n
24 df
0.9538 difference (Son's Height   - Father's Height)
23.3263 pooled variance
4.8297 pooled std. dev.
1.8944 standard error of difference
0 hypothesized difference
0.504 t
.3096 p-value (one-tailed, upper)

Since the p-value (0.3096) is greater than the significance level (0.05), we cannot reject the null hypothesis.

Therefore, we have insufficient evidence to conclude that sons are taller than their fathers on average.

Please give me a thumbs-up if this helps you out. Thank you!

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