Question

A researcher randomly selects 6 fathers who have adult sons and records the​ fathers' and​ sons'...

A researcher randomly selects 6 fathers who have adult sons and records the​ fathers' and​ sons' heights to obtain the data shown in the table below. Test the claim that sons are taller than their fathers at the

alpha equals 0.10α=0.10

level of significance. The normal probability plot and boxplot indicate that the differences are approximately normally distributed with no outliers so the use of a paired​ t-test is reasonable.

Observation

1

2

3

4

5

6

Height of father​ (in inches)

73.5

69.1

71.1

73.5

71.6

65.8

Height of son​ (in inches)

74.8

67.3

69.5

72.8

75.7

68.4

What are the hypotheses for the​ t-test? Note that population 1 is fathers and population 2 is sons.

A.

H0​:

muμ1equals=muμ2

Ha​:

muμ1less than<muμ2

B.

H0​:

muμ1greater than or equals≥muμ2

Ha​:

muμ1less than<muμ2

C.

H0​:

muμ1equals=muμ2

Ha​:

muμ1greater than>muμ2

D.

H0​:

muμ1equals=muμ2

Ha​:

muμ1not equals≠muμ2

Find the test statistic.

tequals=nothing

​(Round to three decimal places as​ needed.)

Find the critical​ value(s).

The critical​ value(s) is/are

nothing.

​(Round to three decimal places as needed. Use a comma to separate answers as​ needed.)

What is the correct conclusion for the hypothesis​ test?

A.

Do not rejectDo not reject

Upper H 0H0.

There

is notis not

sufficient evidence that sons are taller than their fathers.

B.

Do not rejectDo not reject

Upper H 0H0.

There

isis

sufficient evidence that sons are taller than their fathers.

C.

RejectReject

Upper H 0H0.

There

is notis not

sufficient evidence that sons are taller than their fathers.

D.

RejectReject

Upper H 0H0.

There

isis

sufficient evidence that sons are taller than their fathers.

Click to select your answer(s).

0 0
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Answer #1

for 0.1 level with left tailed test and n-1-5 degree of freedom, critical value of t Decision rule 1.476 reject Ho if test statistic t<-1.476 Father 73.5 69.1 71.1 73.5 71.6 65.8 S. No 1 2 difference(d) x1-x2 1.3 Son 74.8 67.3 69.5 72.8 75.7 68.4 1.690000 3.240000 2.560000 0.490000 16.810000 6.760000 2d2-31.55 4. 0.7 total mean dbar 0.650 degree of freedom -n-1 Std deviaiton SpV(Ed-(zd)/n)/(n-1) - std error-se - so/vn = test statistic(d-ud)/Se - 5.000 2.4089 0.983 0.661

from above:

What are the hypotheses for the​ t-test? option A is correct

test statistic t =-0.661

critical​ value(s) is t = -1.476

correct conclusion for the hypothesis​ test? option A is correct

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