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A set of Helmholtz coils has a coil diameter of D = 0.062 m , with...


A set of Helmholtz coils has a coil diameter of D = 0.062 m , with N = 18 turns in each coil, and the current flowing through the coils is I = 1.6 A. What will the magnitude of the magnetic field at the centre of the Helmholtz coils be? Express answer to two significant figures.

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Answer #1

magnitude of magnetic field = uo ( NI)/2R

where N = number of turns

I = current

R = radius

B = 4pi*10^-7*(18*1.6) / 0.062

= 5.84*10^-4 T

= 0.58 mT

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