The drug Eliquis is used to help prevent blood clots in certain patients. In clinical trials,...
The drug Eliquis is used to help prevent blood clots in certain patients. In clinical trials, among 2924 patients treated with Eliquis, 153 developed the adverse reaction of nausea. Construct a 99% confidence interval for the proportion of adverse reactions. Interpret your results in one or two sentences. Round your interval values to three decimal places.
Homework Answers
We have given,
x=153
n=2924
Estimate for sample proportion
Level of significance is =1-0.99=0.01
Z critical value(using Z table)=2.58
Confidence interval formula is
=(0.042,0.063)
Lower limit for confidence interval=0.042
Upper limit for confidence interval=0.063
We are 99% confident that population proportion of adverse reactions is between 0.042 to 0.063
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The drug Eliquis is used to help prevent blood clots in certain
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10. Eliquis The drug Eliquis (apixaban) is used to help prevent blood clots in certain patients. In clinical trials, among 5924 patients treated with Eliquis, 153 developed the adverse reaction of nausea (based on data from Bristol-Myers Squibb Co.). Use a 0.05 significance level to test the claim that 3% of Elíquis users develop nausea. Does nausea appear to be a problematic adverse reaction? irwOK a dultg or
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10. Eliquis The drug Eliquis (apixaban) is used to help prevent blood clots in certain patients. In clinical trials, among 5924 patients treated with Eliquis, 153 developed the adverse reaction of nausea (based on data from Bristol-Myers Squibb Co.). Use a 0.05 significance level to test the claim that 3% of Eliquis users develop nausea. Does nausea appear to be a problematic adverse reaction?
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Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 5970 patients treated with this drug. 150 developed the adverse reaction of nausea. Use a 0.10 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? Identity the null and alternative hypotheses for this test. Choose the correct answer below, O A. Ho:p*0.03 H, p=0.03 OB. Ho: p=0.03 Hp+0.03 Oc. Họ...
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