Element X has three common isotopes. One has a mass of 132.033 and is 18.33% abundant. Another with a mass of 131.045 is 20.67% abundant. If the remaining one has a mass of 130.032, determine the average mass of this element.
Element X has three common isotopes. One has a mass of 132.033 and is 18.33% abundant....
magnesium is the ninth most abundant element in the universe and has three isotopes, given the fellowing information table and the average atomic mass of magnesium is 24.31amu, determine and write the atomic symbol of the unknown isotope of magnesium
A fictitious element, Beaverium, has two naturally occurring isotopes. 285Bv has a mass of 284.67 amu and is 42.744% abundant. 288Bv has a mass of 287.73 amu and is 57.256% abundant. What is the average atomic mass (in amu) of Beaverium?
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
9. Bromine has two abundant isotopes, "Br (51%) and Br (49%). Chlorine has two abundant isotopes, 3$CI (75%) and "CI (25%). Carbon and oxygen have only one abundant isotope each. Which of the following molecules would you expect to show three molecular ion peaks with significant intensity in a standard-resolution mass spectrum? A. 1-bromopropane 1,2-dibromo-3-chlorobenzene 1,3-dibromobenzene 3-chloro-1-octanol None of the above
In another universe, element trinium has two naturally occurring isotopes, 34Tr and 35Tr. One of these has a natural abundance of about 10% and one is about 90%. If the atomic mass of trinium is 34.1 amu, what is most likely to be the isotope that is about 90% abundant? options: trinium-34 trinium-35
An unknown element (Element X) has three naturally occurring isotopes. Complete the table by filling in the missing percent abundance (2 decimal places). Then calculate the atomic mass of element X (1 decimal place) and determine its identity by filling in its atomic symbol (case sensitive). Isotope Abundance (%) Atomic Mass (amu) 23.985042 1 78.99 2 24.985837 10.00 3 25.982593 amu Atomic mass of element X (1 decimal place): Atomic symbol of element X:
An element has three naturally occurring isotopes with masses as listed below. The average atomic mass of this element is 28.08 amu. Determine the two missing percent abundances.^28X 27.98 amu % abundance =^29X 28.98 amu % abundance = 4.68 %^30X 29.97 amu % abundance =
1. An element, A, has 2 naturally occurring isotopes. Isotope-1 has a mass of 40.00 amu, and isotope-2 has a mass of 44.00 amu. If isotope-1 is 4 times more abundant than the isotope-2, what is the mass of element A?
4. The element boron has two naturally occurring isotopes. One has atomic mass 10.0129 u, while the other has atomic mass 11.0093 u. The average atomic mass of boron is 10.811 u. Determine the percentage occurrence of each isotope.
A fictitious element Z has an average atomic mass of 223.16 u. Element Z has two naturally occuring isotopes. The more abundant isotope has an exact mass of 224.45 u and a relative abundance of 65.25 % . Calculate the exact mass of the second isotope.