Question

(Count positive and negative numbers and compute the average of numbers)
Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, and computes the total and average of the input values (not counting zeros). Your program ends with the input 0. Display the average as a floating-point number.
If you entire input is 0, display 'No numbers are entered except 0.'

*So I think my code is looping because the compiler says it takes too long. Could I have someone take a look at my code. Thanks!

#include <iostream>
using namespace std;

   int main()
   {
       int numberOfPositives = 0, numberOfNegatives = 0, total = 0, count = 0;
        int number;
       float average;

       cout << "Enter an integer: ";
       cin >> number;

       while (number != 0) {
           total += number;
           count++;

           if (number > 0) {
               numberOfPositives++;
           }

           else if (number < 0) {
               numberOfNegatives++;
           }

           else if (total = 0) {
               cout << "No numbers are entered except 0.";
           }
           average = total / count;
       }
           cout << "The number of positives is " << numberOfPositives;
           cout << "The number of negatives is " << numberOfNegatives;
           cout << "The total is " << total;
           cout << "The average is " << average;
           return 0;
       }
       

Answer 1

ANSWER : Here I am giving the code and output if you have any problem then comment or like my solution. Here I am taking a list to store the numbers which user enters because we have to find total , avarage and numbers of postive and negatives and it not possible without storing the data.

CODE:

#include <iostream>
#include <list>
#include <iterator>
using namespace std;

int main()
{
int numberOfPositives = 0, numberOfNegatives = 0, total = 0, count = 0;
int number;
float average;
list <int> lst; // taking a list because user can enter many numbers untill 0 is not inputed.
while(1){
cout << "Enter an integer: ";
cin >> number;
if(number ==0)
break;
else{
lst.push_back(number);
}
}
list <int> :: iterator it; // iterator of the list.
for(it = lst.begin(); it != lst.end(); ++it) {
total += *it;
count++;

if (*it > 0) {
numberOfPositives++;
}

else if (*it < 0) {
numberOfNegatives++;
}

else if (total = 0) {
cout << "No numbers are entered except 0.";
}
}

average = (float)total / count;
  
cout << " The number of positives is " << numberOfPositives;
cout << " The number of negatives is " << numberOfNegatives;
cout << " The total is " << total;
cout << " The average is " << average;
return 0;
}

OUTPUT: