ZuoTi.Pro
Question

The null and alternative hypotheses for a population proportion, as well as the sample results, are...

The null and alternative hypotheses for a population proportion, as well as the sample results, are given. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information.


Hypotheses: H0:p=0.5 vs Ha:p<⁢0.5;
Sample data: p^=38/100=0.38 with n=100

Round the p-value to three decimal places.

p-value = Enter your answer in accordance to the question statement

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Proportion = 0.5

Total number of sample (n) = 100

number of favourable events (X) = 38

We are interested in testing the hypothesis

Since P-value of a two tailed test is equal to

P = (0.008197535924596131)

P = 0.0082

Here, the P-value is less than the level of significance 0.05; reject the null hypothesis

0 0
Add a comment
Know the answer?
Add Answer to:
The null and alternative hypotheses for a population proportion, as well as the sample results, are...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The null and alternative hypotheses for a test are given, as well as some information about...

    The null and alternative hypotheses for a test are given, as well as some information about the actual sample and the statistic that is computed for each randomization sample. Indicate where the randomization distribution will be centered. Ho : p= 0 vs Ha : p=0 Sample: r = -0.23, n = 40 Randomization statistic: r

  • The null and alternative hypotheses for a test are given, as well as some information about...

    The null and alternative hypotheses for a test are given, as well as some information about the actual sample and the statistic that is computed for each randomization sample. Indicate where the randomization distribution will be centered.            Ho = p1 = p2     vs. ha p1 < p2 Sample: p̂1 = 0.3, n= 20    p̂2 = 0.167, n=12 Randomization statistic: p̂1 - p̂2 Answer _______________

  • The null and alternative hypotheses for a test are given, as well as some information about...

    The null and alternative hypotheses for a test are given, as well as some information about the actual sample and the statistic that is computed for each randomization sample. Indicate where the randomization distribution will be centered.               Ho: p1 = p2          vs.        Ha: p1>p2 Sample: p̂1 = 0.3, n=20, p̂2 = 0.467 n=12 Randomization statistic p̂1 - p̂2 P.S. The answer is not -0.167

  • The p-value associated with the null and alternative hypotheses for the two sample t-test is 0.045,...

    The p-value associated with the null and alternative hypotheses for the two sample t-test is 0.045, choose the best conclusion: EXPLAIN a. The alternative hypothesis is true.            b. The null hypothesis is true. c. There is suggestive evidence that the average tip for good weather days is greater than the average tip for bad weather days. d. There is no evidence that the average tip for good weather days is greater than the average tip for bad weather days.

  • Given the following null and alternative hypotheses, the test statistic from the sample data is z=1.875z=1.875....

    Given the following null and alternative hypotheses, the test statistic from the sample data is z=1.875z=1.875. If the significance level of 0.05 which results in a critical value of 1.645, what is the conclusion as it relates to the null hypothesis? H0:p=0.22 H1:p>0.22 Fail to reject the alternative hypothesis Reject the null hypothesis Fail to reject the null hypothesis Support the null hypothesis

  • 1. To test for the effectiveness of Hydroxychloroquine on preventing COVID-19 symptoms, University of Michigan is...

    1. To test for the effectiveness of Hydroxychloroquine on preventing COVID-19 symptoms, University of Michigan is conducting a clinical trial. They are recruiting people by asking those who are healthcare workers and have had a high exposure to the disease to contact them to be enrolled in the study. They ultimate receive 10500 responses. Which option best characterizes this sample? Select one: a. Voluntary response sample 0 b. Simple random sample 0 c. Cluster sample 0 d. Systematic random sample...

  • Test the claim that the proportion of people who own cats is larger than 20% at...

    Test the claim that the proportion of people who own cats is larger than 20% at the 0.005 significance level. The null and alternative hypothesis would be: H0:μ≤0.2H0:μ≤0.2 Ha:μ>0.2Ha:μ>0.2 H0:μ≥0.2H0:μ≥0.2 Ha:μ<0.2Ha:μ<0.2 H0:p≤0.2H0:p≤0.2 Ha:p>0.2Ha:p>0.2 H0:p≥0.2H0:p≥0.2 Ha:p<0.2Ha:p<0.2 H0:p=0.2H0:p=0.2 Ha:p≠0.2Ha:p≠0.2 H0:μ=0.2H0:μ=0.2 Ha:μ≠0.2Ha:μ≠0.2 The test is: left-tailed two-tailed right-tailed Based on a sample of 100 people, 26% owned cats The p-value is:  (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis Test the claim that the proportion...

  • The two-way table shows sample results and hypotheses are given for a test for a difference...

    The two-way table shows sample results and hypotheses are given for a test for a difference in the proportion saying yes between the two groups. Test H0 : p1=p2 vs Ha : p1>p2 using the results:     Yes No Total Group 1 128 72 200 Group 2 55 45 100 Total 183 117 300 Find the value of the standardized z-test statistic and then use the standard normal distribution to find the p-value. Round your answers to three decimal places....

  • QUICK is 12.5 to 11.1. Using the confidence interval give (a) A 95% confidence intervalfor a...

    QUICK is 12.5 to 11.1. Using the confidence interval give (a) A 95% confidence intervalfor a mean (b) A 90% confidence interval for a proportion p is 0.62 to 0.80. Testing Ho: p=0.65 vs H.: p=0.65. (c) A 99% confidence intervalfor a difference in proportions is - 0.10 to 0.20. Testing Ho: P = P2 vs Ho: P. #P2. Example 3: Evaluating Drugs to Fight Cocaine Addiction In a randomized experimenton treating cocaine addiction, 48 cocaine addicts who were trying...

  • Claim: 77% of workers got their job through college. Express the null and alternative hypotheses in...

    Claim: 77% of workers got their job through college. Express the null and alternative hypotheses in symbolic form for this claim (enter as a percentage). H0:pH0:p H1:pH1:p Use the following codes to enter the following symbols:      ≥≥ enter >=      ≤≤ enter <=      ≠≠ enter !=

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT