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A roller coaster starts at position A with speedv D 1m=sasitgoesoverthe initial hill, height h1 D...

A roller coaster starts at position A with speedv D 1m=sasitgoesoverthe initial hill, height h1 D 100 m, as shown in the diagram. Assuming no loss in Energy (i.e. no friction), determine the speed at the following locations: a. (3 Points) Position B at height h2 D50m b. (3 Points) Position C at height h3 D75m c. (3 Points) Position D at ground level, height h D 0 m

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Answer #1

a)

m = mass of the roller coaster

At position A :

v1 = 1 m/s

h1 = 100 m

At position B :

v2 = ?

h2 = 50 m

Using conservation of energy between A and B

KE at B + PE at B = KE at A + PE at A

(0.5) m v22 + mg h2 = (0.5) m v12 + mg h1

(0.5) v22 + g h2 = (0.5) v12 + g h1

(0.5) v22 + (9.8 x 50) = (0.5) (1)2 + (9.8 x 100)

v2 = 31.3 m/s

b)

m = mass of the roller coaster

At position A :

v1 = 1 m/s

h1 = 100 m

At position C :

v3 = ?

h3 = 75 m

Using conservation of energy between A and C

KE at C + PE at C = KE at A + PE at A

(0.5) m v32 + mg h3 = (0.5) m v12 + mg h1

(0.5) v32 + g h3 = (0.5) v12 + g h1

(0.5) v32 + (9.8 x 75) = (0.5) (1)2 + (9.8 x 100)

v3 = 22.2 m/s

c)

m = mass of the roller coaster

At position A :

v1 = 1 m/s

h1 = 100 m

At position D :

v4 = ?

h4 = 0 m

Using conservation of energy between A and D

KE at D + PE at D = KE at A + PE at A

(0.5) m v42 + mg h4 = (0.5) m v12 + mg h1

(0.5) v42 + g h4 = (0.5) v12 + g h1

(0.5) v32 + (9.8 x 0) = (0.5) (1)2 + (9.8 x 100)

v4 = 44.3 m/s

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