1. P(Correct) = 1/4 = 0.25
Passing grade is 60% so student has to get atleast 20*0.6 i.e. 12 correct.
Hence,
P(12 or more correct)
= 1 - P(11 or less correct)
= 1 - binom.dist(11, 20, 0.25, True) [Excel Formula]
= 0.0009
2. P(First correct within 3 attempts)
= P(Correct in 1st) + P(Wrong in 1st; Correct in 2nd) + P(Wrong in 1st and 2nd; Correct in 3rd)
= 0.60 + 0.40*0.60 + 0.40*0.40*0.60
= 0.936
3. The distribution of variable X which represents the number of questions attempted to get the first correct answer will be geometric distribution. Hence,
Expected number of attempts to get the first correct = 1/p = 1/0.25 = 4
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