1. The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 69.6 for a sample of size 27 and standard deviation 11.5. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 80% confidence level). Assume the data is from a normally distributed population.
Enter your answer as a tri-linear inequality accurate to three
decimal places.
_____ < μ < _____
2. Express the confidence interval (25.5%,37.5%)(25.5%,37.5%) in
the form of ˆp±Ep^±E.
______% ± ______%
Solution :
1)
t /2,df = 1.315
Margin of error = E = t/2,df * (s /n)
= 1.315 * (11.5 / 27)
Margin of error = E = 2.910
The 80% confidence interval estimate of the population mean is,
- E < < + E
69.6 - 2.910 < < 69.6 + 2.910
66.690 < < 72.510
2)
Point estimate = = (25.5% + 37.5%) / 2 = 31.5%
Margin of error = E = Upper confidence interval - = 37.5% - 31.5% = 6%
In the form of :
- E < p < + E is,
31.5% 6%
1. The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average,...
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