A communications satellite is in a synchronous orbit that is 3.34×107 m directly above the equator....
A communications satellite is in a synchronous orbit that is 3.34×107 m directly above the equator. The satellite is located midway between Quito, Equador, and Belem, Brazil, two cities almost on the equator that are separated by a distance of 3.16×106 m. Calculate the time it takes for a telephone call to go by way of satellite between these cities. Ignore the curvature of the earth.
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A communications satellite is in a synchronous orbit that is
3.34×107 m directly above the equator....
A geostationary communications satellite orbits the earth directly above the equator at an altitude of 34800...
A geostationary communications satellite orbits the earth directly above the equator at an altitude of 34800 km .Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back.Would this delay be noticeable in a conversation?
A satellite is launched to orbit the Earth at an altitude of 3.55 107 m for...
A satellite is launched to orbit the Earth at an altitude of 3.55 107 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97 1024 kg and its radius 6.38 106 m. (a) What is the orbital period, in hours, of this GPS satellite? (b) With what speed, in m/s, does it orbit the Earth?
A synchronous satellite, which always remains above the same point on a planet's equator, is put...
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A 1740-kg communications satellite is released from a space shuttle to initially orbit the Earth at...
A 1740-kg communications satellite is released from a space shuttle to initially orbit the Earth at a radius of 9. 106 m. After being deployed, the satellite's rockets are fired to put it into a higher altitude orbit of radius 4. 107 m. What is the minimum mechanical energy supplied by the rockets to effect this change in orbit?
A synchronous satellite, which always remains above the same point on a planet's equator, is put...
A synchronous satellite, which always remains above the same
point on a planet's equator, is put in orbit around Mars so that
scientists can study a surface feature. Mars rotates once every
24.6 h. Use the data of this table to find the altitude of the
satellite. Please show how you figured this out step by step!
Useful Planetary Data Mean 10-19 ..3 Mean Distance Radius (m Mass (kg) Period (s) Body from Sun (m) 2.48 X 10 7.60 x...
Coordinate transformations: Consider a satellite in Earth orbit. The position vector of the satellite in ECEF...
Coordinate transformations: Consider a satellite in Earth orbit. The position vector of the satellite in ECEF coordinates (pe) is equal to: 1x 106 m pe -4.2198 -26.428 9.4295 (1) X When the satellite is at these position coordinates, its velocity vector in ECEF coor- dinates is given by: ]m/s. 2941.4 48343 2667.2 (2) Answer the following questions (you may want to write MATLAB scripts to solve some or all of the problems). (a) What are the satellites's geodetic position coordinates?...
Find the orbital speed of a satellite in a geosynchronous circular orbit 3.45×107 m above the...
Find the orbital speed of a satellite in a geosynchronous circular orbit 3.45×107 m above the surface of the Earth.
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication...
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication around the world. (You may consider that the mass of the satellite is m, mass of the earth is M(6x1024 kg), center-to-center distance between the satellite and the earth is r, radius of the earth is R(6.4×106 m), and the universal gravitational constant G = 6.67x10-11 N.m2/kg2.) Satellite Earth Applying newton's 2nd law, write an equation describing the circular motion of the satellite. (4...
Many communication satellites are placed in a circular orbit around the Earth at a radius where...
Many communication satellites are placed in a circular orbit around the Earth at a radius where the period (the time to go around the Earth once) is 24 hours. If the satellite is above some point on the equator, it stays above that point as the Earth rotates, so that as viewed from the rotating Earth the satellite appears to be motionless. That is why you see dish antennas pointing at a "fixed" point in space. (a) Calculate the radius...
Pluto -1.4 x 10 1.5 x 10 1.02 X 1 Moon 7.36 x 1022 1.991 x...
Pluto -1.4 x 10 1.5 x 10 1.02 X 1 Moon 7.36 x 1022 1.991 x 1030 1.74 x 106 6.96 x 108 Sun -13 POINTS SERCP11 7.5.P.044. A 716-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m /s (b) Find the period of its revolution. (c) Find the gravitational force acting on it. Need Help? Read it -18 POINTS SERCP9 7.P.031.MI.FB. A...
A synchronous satellite, which always remains above the same
point on a planet's equator, is put in orbit around Mars so that
scientists can study a surface feature. Mars rotates once every
24.6 h. Use the data of this table to find the altitude of the
satellite. Please show how you figured this out step by step!
Useful Planetary Data Mean 10-19 ..3 Mean Distance Radius (m Mass (kg) Period (s) Body from Sun (m) 2.48 X 10 7.60 x...
Coordinate transformations: Consider a satellite in Earth orbit. The position vector of the satellite in ECEF coordinates (pe) is equal to: 1x 106 m pe -4.2198 -26.428 9.4295 (1) X When the satellite is at these position coordinates, its velocity vector in ECEF coor- dinates is given by: ]m/s. 2941.4 48343 2667.2 (2) Answer the following questions (you may want to write MATLAB scripts to solve some or all of the problems). (a) What are the satellites's geodetic position coordinates?...
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication around the world. (You may consider that the mass of the satellite is m, mass of the earth is M(6x1024 kg), center-to-center distance between the satellite and the earth is r, radius of the earth is R(6.4×106 m), and the universal gravitational constant G = 6.67x10-11 N.m2/kg2.) Satellite Earth Applying newton's 2nd law, write an equation describing the circular motion of the satellite. (4...
Pluto -1.4 x 10 1.5 x 10 1.02 X 1 Moon 7.36 x 1022 1.991 x 1030 1.74 x 106 6.96 x 108 Sun -13 POINTS SERCP11 7.5.P.044. A 716-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m /s (b) Find the period of its revolution. (c) Find the gravitational force acting on it. Need Help? Read it -18 POINTS SERCP9 7.P.031.MI.FB. A...
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