Question

Write an Algorithm in Pseudocode for the Exercises Below

1. Add 5 numbers that a user enters by keyboard and display the Total on screen.
2. Compute the area of a rectangle and display on screen based on length and width values that the user enters by keyboard.
3. Compute the new price for a product that’s on sale for 10% off. Display new calculated price on screen. Assume current price is $25.00.
4. Add the prices of an order of fries, a burger and a drink. Calculate the tax based on the sales tax rate that customer entered by keyboard and tell the customer their total on screen.
   Assume the following Beef-A-Roo prices: fries = $1.69, burger = $3.39, and drink = $1.69.
5. Subtract 2 numbers user enters by keyboard. Display the following result text to the screen - If the result is positive, say “Positive”; if the result is negative, say “Negative”. If the result is 0, say “Zero”.

Answer 1

1. Add 5 numbers :

BEGIN

ARRAY arr[5], sum

FOR i = 0 to arr.length - 1

OUTPUT("ENTER NUMBER"+ (i + 1) + " : ")

INPUT arr[i]  

sum = sum + arr[i]

ENDFOR

OUTPUT sum

END

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2. AREA OF RECTANGLE

BEGIN

NUMBER length, breadth

OUTPUT("ENTER LENGTH : ")

INPUT length

OUTPUT("ENTER BREADTH : ")

INPUT breadth

OUTPUT("AREA : " + (length * breadth ))

END

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3. NEW PRICE AFTER TAX

BEGIN

NUMBER curr_price = 25.00, tax = 10

NUMBER new_price

new_price = curr_price + ( curr_price * ( tax / 100 ) )

OUTPUT new_price

END

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4. ADD PRICE OF ORDERS

BEGIN

NUMBER fries_price = 1.69

NUMBER burger_price = 3.39

NUMBER drink_price = 1.69

NUMBER tax_rate, total_price

OUTPUT("ENTER TAXT RATE : ")

INPUT tax_rate

total_price = ( fries_price + burger_price + drink_price )+(( fries_price + burger_price + drink_price ) * tax_rate /100)

OUTPUT total_price

END

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5 Positive or negative numbers :

BEGIN

NUMBER num1, num2, result

OUTPUT ("ENTER NUM1 : ")

INPUT num1

OUTPUT ("ENTER NUM2 : ")

INPUT num2

result = num1 - num2

IF result > 0

  OUTPUT("POSITIVE")

ELSE IF result < 0

OUTPUT("NEGATIVE")

ELSE

OUTPUT("ZERO")

END

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