A six sided die has been rolled 3 times to randomly define three digits of a...
A six sided die has been rolled 3 times to randomly define three digits of a code. We know that the code is not 111 or 666. What is the chance of finding the code in the first attempt?
Homework Answers
Solution:
A die has total six outputs from 1 to 6.
So, number of three digit codes = 6*6*6 = 216
We are given that the code is not 111 or 666.
So, number of available codes = 216 – 2 = 214
Probability of finding the code in the first attempt = 1/214 = 0.004673
Required probability = 0.004673
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