A regular six-sided die is rolled 9 times. What is the probability of getting a 1 or 6 on exactly 7 of those rolls?
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Answer:
Prob ( getting 1 or 6 ) on a 6 sided dice = 2/6 = 1/3
Now when the die is rolled 9 times, we choose 7 rolls out of these
=> 9C7
Now in the remaining rolls we have to get other numbers than 1 ir 6 => 4/6 = 2/3
Hence the total probability
=> 9C7 * (1/3)7* (2/3) * (2/3)
= 0.01646 * 4/9
= 0.0077316 or 144/19683
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