Question

A pendulum bob, with mass 1.60 kg, is held at rest initially in a horizontal position...

A pendulum bob, with mass 1.60 kg, is held at rest initially in a horizontal position as shown. The string has negligible mass and a length of 1.20 m. The bob is then released from rest. It swings down and collides with a block of mass 2.40 kg initially at rest. Ignore air resistance.

a) Use the Principle of Conservation of Mechanical Energy to find the speed of the pendulum bob just before the collision.

b) (The bob collides with the block. The bob recoils with a speed of 0.100 m/s. What is the speed of the block just after the collision?

c) Is the collision elastic or inelastic? You must show how you arrived at your conclusion (i.e. show all work).

d) \The block is displaced a total of 2.00 m to the right after the collision. Use the WorkEnergy Theorem to find the coefficient of kinetic friction between the block and surface.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A pendulum bob, with mass 1.60 kg, is held at rest initially in a horizontal position...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A bullet of mass 8 g is fired into a 1.2 kg ballistic pendulum (a block...

    A bullet of mass 8 g is fired into a 1.2 kg ballistic pendulum (a block of wood acting as the pendulum bob of a thin metal arm attached to a low friction pivot point) that is initially at rest. The bullet exits the block of wood with a speed of 180 m/s and the wooden block swings from its lowest point to a maximum height of 9.2 cm above that location. Determine the velocity of the bullet before it...

  • A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a...

    A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.900 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3. Assume that the blocks slide without...

  • A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a...

    A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.900 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3. Assume that the blocks slide without...

  • A pendulum of length L = 1.0 meter and bob with mass m = 1.0 kg...

    A pendulum of length L = 1.0 meter and bob with mass m = 1.0 kg is released from rest at an angle 0 = 30' from the vertical. When the pendulum reaches the vertical position, the bob strikes a mass M= 3.0 kg that is resting on a frictionless table that has a height h = 0.85m. (a). When the pendulum reaches the vertical position, calculate the speed of the bob just before it strikes the box. (6 marks]...

  • A 1.9-kg ball is attached to the end of a 2.6-m string to form a pendulum....

    A 1.9-kg ball is attached to the end of a 2.6-m string to form a pendulum. This pendulum is released from rest with a string horizontal. At the lowest point in its swing when it is moving horizontally, the ball collides elastically with a 2.5-kg block initially at rest on a horizontal frictionless surface. What is the speed of the block just after the collision? Show all the important physics steps.

  • A block of mass m -2.00 kg collides head on with a block of mass m-...

    A block of mass m -2.00 kg collides head on with a block of mass m- 10.0 kg initially at rest on a rough horizontal surface. The block m strikes m2 with a speed of 4.00 m/s. Immediately after the very brief inelastic collision, the 2.00 kg block bounces back with a speed of 1.20 m/s. Ignore the effect of friction during the collision. (a) 4pts.] Calculate the speed of the 10.0 kg block immediately after the collision. (b) 4...

  • A block of mass mi 1.60 kg moving at v1 2.00 m/s undergoes a completely inelastic...

    A block of mass mi 1.60 kg moving at v1 2.00 m/s undergoes a completely inelastic collision with a Part A telLionary block of mass m = 0.600 kg. The blocks time, the two-block system collides inelastically with a third block, of mass m3 = 2.50 kg , which is initially at rest. The three blocks then move, stuck together, with speed u3.(Figure 1) Assume that the blocks slide without friction. Find the ratio of the velocity v2 of the...

  • A 2.0-kg mass moving at 5.0 m/s suddenly collides head-on with a 3.0-kg mass at rest....

    A 2.0-kg mass moving at 5.0 m/s suddenly collides head-on with a 3.0-kg mass at rest. If the collision is perfectly inelastic, what is the speed of the masses just after the collision? 2.5 m/s 10 m/s 2.0 m/s 0 m/s, since the collision is inelastic

  • A block of mass m1 = 1.70 kg moving at v1 = 2.00 m/sundergoes a completely...

    A block of mass m1 = 1.70 kg moving at v1 = 2.00 m/sundergoes a completely inelastic collision with a stationary block of mass m2 = 0.300 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3.(Figure 1) Assume that the blocks slide without...

  • As shown in the figure below, object m1 = 1.60 kg starts at an initial height...

    As shown in the figure below, object m1 = 1.60 kg starts at an initial height hij = 0.305 m and speed V1 = 4.00 m/s, swings downward and strikes in an elastic collision) object m2 = 4.55 kg which is initially at rest. 4.00 m/s m2 (a) Determine the speed of m(in m/s) just before the collision. X After you are convinced that energy is conserved as m, swings downward for the collision with me, see if you can...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT