two equal charges separated by a distance of 68cm, exert a force of .70N on each...
Two charges q1 and q2 are separated by a distance d and exert a force F on each other. What is the new force F ′ , if charge 1 is increased to q ′1 = 5 q1, charge 2 is decreased to q ′2 = q2 / 2, and the distance is decreased to d ′ = d / 2? Can you work it out step by step and explain why please, I am having trouble with this concept.
Two charges of equal magnitude exert an attractive force of 7.5×10-4 N on each other. If the magnitude of each charge is +2.9µ C, how far apart are the charges?
Two charges of equal magnitude exert an attractive force of 6.5×10-4 N on each other. If the magnitude of each charge is +1.7μ C, how far apart are the charges?
Two charges of equal magnitude exert an attractive force of 8.0×10-4 N on each other. If the magnitude of each charge is +2.6μ C, how far apart are the charges?
Two charges of equal magnitude exert an attractive force of 5.5×10-4 N on each other. If the magnitude of each charge is +1.8μ C, how far apart are the charges?
Two Charges Qj and Q2 are a distance R apart and they exert a force F on each other. - Write the expression for the magnitude of the force existing between the two charges; - What is the new value of the force if the charges are now 1/3 R; 2R, 3R, and 4 R apart? Explain your results based on the results of the lab.
Two particles carrying charges gn and q2 are separated by a distance r and exert an electric force FE on each other. Part A If gh is doubled, what change must you make to one of the other variables in order to keep the magnitude F constant? There is more than one answer Check all that apply. should be doubled. □ r should be changed to r/v2 should be halved. r should be changed to v2r □ should be changed...
Two point charges separated by a distance of 6 cm, are attracted to each other with a force of 20 N. What is the magnitude of the force at 3 cm separation? Two point charges separated by a distance of 6 cm, are attracted to each other with a force of 20 N. What is the magnitude of the force at 3 cm separation? Answer:
10. Compare the mag itude of the force between two equal charges separated a distance of 1.00 km, to the magnitude of the gravitational force acting on a 1.00 kg mass in Earth's gravitational field near the surface of the Earth.
2. Dipole-dipole force The charge distribution where two equal but opposite charges are separated by a fixed distance a dipole and is very common and important in nature. Consider two dipoles, each consisting of charges ±q separated by a distance δ. The axes of two dipoles are parallel and their midpoints are separated by a distance r. One is inverted compared to the other. See the figure tq +9 (a) Calculate the force exerted on each dipole by the other...