How many grams of H2O can be prepared from 11.25grams of NH3 and 56.03g of O2in the following equation?
4NH3(g) + 5O2(g) arrow 4NO+ 6H2O(g)
How many grams of H2O can be prepared from 11.25grams of NH3 and 56.03g of O2in...
How many grams of NO and of H2O form? Enter your answers numerically separated by a comma. How many grams of the excess reactant remain after the limiting reactant is completely consumed? One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) In a certain experiment, 1.50 g of NH3 reacts with 2.75 g of O2.
From the following balanced equation, 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l) how many grams of NO can be formed from 3.78g O2? Options: (a) 2.55g (b) 2.84g (c) 4.43g (d) 5.04g
If the reaction consumes (uses up) 31.7 moles of ammonia, how many grams of water will be produced using the following equation? 4NH3 + 5O2 g 4NO + 6H2O
How many grams of N2 are produced from 100.0 g of NH3 according to the following reaction? 4NH3 + 6NO ------ > 5N2 + 6H20 Calculate the mass (g) of H2O needed to produce 150 g of Mg(OH)2 according to the equation: Mg2N2 + 6H2O ----- > 3Mg(OH)2 + 2NH3
One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) In a certain experiment, 1.85 g of NH3 reacts with 3.39 g of O2. 1) How many grams of NO and of H2O form? 2) How many grams of the excess reactant remain after the limiting reactant is completely consumed?
One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) In a certain experiment, 2.05 g of NH3 reacts with 3.76 g of O2. How many grams of NO and of H2O form? Enter your answers numerically separated by a comma.
1) Ammonia, NH3, reacts with molecular oxygen, O2, to form nitric oxide, NO, and water:4NH3(g) + 5O2(g) = 4NO (g) +6H2O(l)A. What is the limiting reactant and what is the theoretical yield of NO?B. What is the theoretical yield of H2O?C. How many grams of excess reagent will be left over?D. If the actual yield of NO had been 91 g, what would be the percent yield of the reaction
How many grams of H2O can be prepared from the reaction of 12.1 g of Mg(OH)2 and 5.31 g of HCl according to the following chemical equation?
How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l) according to the following chemical equation? 4NH3 (g) + 5O2 (g) ---> 4NO (g) +6H2O (l) Δ H: +1168 kJ a. 342.9 kJ of heat are absorbed. b. 342.9 kJ of heat are released. c. 1372 kJ of heat are absorbed. d. 1372 kJ of heat are released. Please explain your answer.
4NH3 + 502 → 4NO + 6H20 How many moles of H2O will be formed by the complete reaction of 5.25 moles of NH3 with 02? How many grams of H20 will be formed by the complete reaction of 4.75 moles of NH3 with O2?