How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l) according to the following chemical equation?
4NH3 (g) + 5O2 (g) ---> 4NO (g) +6H2O
(l) Δ H: +1168 kJ
a. 342.9 kJ of heat are absorbed.
b. 342.9 kJ of heat are released.
c. 1372 kJ of heat are absorbed.
d. 1372 kJ of heat are released.
Please explain your answer.
The answer is: a. 342.9 kJ of heat are absorbed.
Moles of NH3 = mass/molar mass of NH3
= 20.00/17.03 = 1.1744 mol
Since ΔH is positive, reaction is endothermic and heat is absorbed
Amount of heat absorbed = moles of NH3/4 x ΔH
= 1.1744/4 x 1168
= 342.9 kJ
since ΔH is positive heat is absorbed
no.of moles of ammonia=20/17=1.1765moles
amount of heat absorbed for 1.1765moles of NH3=1168*1.1765/4
=343.538KJ
option A
How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and...
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