Question

How much heat is absorbed/released when 30.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) according to the following chemical equation?
4 NH3(g) + 5 O2(g) ? 4 NO(g) + 6 H2O(l) ?H° = 1168 kJ

Answer 1

The reaction is as follows: 4 NH, (g) +5 02 (g)->4 NO (g) +6 H,o(1) On combustion of 1 mol of NH,,heat of reaction/heat released/heat absorbed per mole of NO(g) released is H 1168 kJ Calculate the moles of NH, as follows Mass of NH 301.76 mol Moles of NH According to reaction stiochiometry, 1 mol of NH: 1168 kJ of heat 1s absorbed heat absorbed- Molecular weight of NH, 17 gmol 1168 kJ -1168 kJ mol1 mo 1168 kJ 292 kJ mol 4 mol heat absorbed when 4 mol of NH reacts Calculate the heat is absorbed as follows heat absorbed Hsticn reactio 292 kJ mol1 x 1.76 mol- 513.92kJ Therefore, the heat absorbed is 513.92 kJ